pex10_5.cpp

数据结构C++代码,经典代码,受益多多,希望大家多多支持

#include <iostream.h>
#pragma hdrstop

// output N in base B <= 10
void intout(long N, int B)
{
	// N/B contains the left-most digits of the number
	// output them. this is the recursive step
	if (N/B != 0)
		intout(N/B,B);
	// output the right-most digit (stopping condition)
	cout << N % B;
}

void main(void)
{
	long N;
	int B;
	
	// read 5 number N, base B pairs. output
	// N in base B
	for(int i=0;i < 5;i++)
	{
		cout << "Enter number N and base B: ";
		cin >> N >> B;
		cout << N << " in base " << B << " is ";
		intout(N,B);
		cout << endl << endl;
	}
}

/*
<Run>

Enter number N and base B: 25 2
25 in base 2 is 11001

Enter number N and base B: 3557 8
3557 in base 8 is 6745

Enter number N and base B: 511 4
511 in base 4 is 13333

Enter number N and base B: 511 8
511 in base 8 is 777

Enter number N and base B: 789453 9
789453 in base 9 is 1432830
*/