📄 find_scale_example.cpp
字号:
// find_scale.cpp// Copyright Paul A. Bristow 2007.// Use, modification and distribution are subject to the// Boost Software License, Version 1.0.// (See accompanying file LICENSE_1_0.txt// or copy at http://www.boost.org/LICENSE_1_0.txt)// Example of finding scale (standard deviation) for normal (Gaussian).// Note that this file contains Quickbook mark-up as well as code// and comments, don't change any of the special comment mark-ups!//[find_scale1/*`First we need some includes to access the __normal_distrib,the algorithms to find scale (and some std output of course).*/#include <boost/math/distributions/normal.hpp> // for normal_distribution using boost::math::normal; // typedef provides default type is double.#include <boost/math/distributions/find_scale.hpp> using boost::math::find_scale; using boost::math::complement; // Needed if you want to use the complement version. using boost::math::policies::policy; // Needed to specify the error handling policy.#include <iostream> using std::cout; using std::endl;#include <iomanip> using std::setw; using std::setprecision;#include <limits> using std::numeric_limits;//] [/find_scale1]int main(){ cout << "Example: Find scale (standard deviation)." << endl; try {//[find_scale2/*`For this example, we will use the standard __normal_distrib,with location (mean) zero and standard deviation (scale) unity.Conveniently, this is also the default for this implementation's constructor.*/ normal N01; // Default 'standard' normal distribution with zero mean double sd = 1.; // and standard deviation is 1./*`Suppose we want to find a different normal distribution with standard deviationso that only fraction p (here 0.001 or 0.1%) are below a certain chosen limit(here -2. standard deviations).*/ double z = -2.; // z to give prob p double p = 0.001; // only 0.1% below z = -2 cout << "Normal distribution with mean = " << N01.location() // aka N01.mean() << ", standard deviation " << N01.scale() // aka N01.standard_deviation() << ", has " << "fraction <= " << z << ", p = " << cdf(N01, z) << endl; cout << "Normal distribution with mean = " << N01.location() << ", standard deviation " << N01.scale() << ", has " << "fraction > " << z << ", p = " << cdf(complement(N01, z)) << endl; // Note: uses complement./*`[preNormal distribution with mean = 0 has fraction <= -2, p = 0.0227501Normal distribution with mean = 0 has fraction > -2, p = 0.97725]Noting that p = 0.02 instead of our target of 0.001,we can now use `find_scale` to give a new standard deviation.*/ double l = N01.location(); double s = find_scale<normal>(z, p, l); cout << "scale (standard deviation) = " << s << endl;/*`that outputs:[prescale (standard deviation) = 0.647201]showing that we need to reduce the standard deviation from 1. to 0.65.Then we can check that we have achieved our objectiveby constructing a new distributionwith the new standard deviation (but same zero mean):*/ normal np001pc(N01.location(), s); /*`And re-calculating the fraction below (and above) our chosen limit.*/ cout << "Normal distribution with mean = " << l << " has " << "fraction <= " << z << ", p = " << cdf(np001pc, z) << endl; cout << "Normal distribution with mean = " << l << " has " << "fraction > " << z << ", p = " << cdf(complement(np001pc, z)) << endl;/*`[preNormal distribution with mean = 0 has fraction <= -2, p = 0.001Normal distribution with mean = 0 has fraction > -2, p = 0.999][h4 Controlling how Errors from find_scale are handled]We can also control the policy for handling various errors.For example, we can define a new (possibly unwise) policy to ignore domain errors ('bad' arguments).Unless we are using the boost::math namespace, we will need:*/ using boost::math::policies::policy; using boost::math::policies::domain_error; using boost::math::policies::ignore_error;/*`Using a typedef is convenient, especially if it is re-used,although it is not required, as the various examples below show.*/ typedef policy<domain_error<ignore_error> > ignore_domain_policy; // find_scale with new policy, using typedef. l = find_scale<normal>(z, p, l, ignore_domain_policy()); // Default policy policy<>, needs using boost::math::policies::policy; l = find_scale<normal>(z, p, l, policy<>()); // Default policy, fully specified. l = find_scale<normal>(z, p, l, boost::math::policies::policy<>()); // New policy, without typedef. l = find_scale<normal>(z, p, l, policy<domain_error<ignore_error> >());/*`If we want to express a probability, say 0.999, that is a complement, `1 - p`we should not even think of writing `find_scale<normal>(z, 1 - p, l)`,but [link why_complements instead], use the __complements version.*/ z = -2.; double q = 0.999; // = 1 - p; // complement of 0.001. sd = find_scale<normal>(complement(z, q, l)); normal np95pc(l, sd); // Same standard_deviation (scale) but with mean(scale) shifted cout << "Normal distribution with mean = " << l << " has " << "fraction <= " << z << " = " << cdf(np95pc, z) << endl; cout << "Normal distribution with mean = " << l << " has " << "fraction > " << z << " = " << cdf(complement(np95pc, z)) << endl;/*`Sadly, it is all too easy to get probabilities the wrong way round,when you may get a warning like this:[preMessage from thrown exception was: Error in function boost::math::find_scale<Dist, Policy>(complement(double, double, double, Policy)): Computed scale (-0.48043523852179076) is <= 0! Was the complement intended?]The default error handling policy is to throw an exception with this message,but if you chose a policy to ignore the error,the (impossible) negative scale is quietly returned.*///] [/find_scale2] } catch(const std::exception& e) { // Always useful to include try & catch blocks because default policies // are to throw exceptions on arguments that cause errors like underflow, overflow. // Lacking try & catch blocks, the program will abort without a message below, // which may give some helpful clues as to the cause of the exception. std::cout << "\n""Message from thrown exception was:\n " << e.what() << std::endl; } return 0;} // int main()//[find_scale_example_output/*`[preExample: Find scale (standard deviation).Normal distribution with mean = 0, standard deviation 1, has fraction <= -2, p = 0.0227501Normal distribution with mean = 0, standard deviation 1, has fraction > -2, p = 0.97725scale (standard deviation) = 0.647201Normal distribution with mean = 0 has fraction <= -2, p = 0.001Normal distribution with mean = 0 has fraction > -2, p = 0.999Normal distribution with mean = 0.946339 has fraction <= -2 = 0.001Normal distribution with mean = 0.946339 has fraction > -2 = 0.999]*///] [/find_scale_example_output]
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -