bessel_yn.hpp
来自「Boost provides free peer-reviewed portab」· HPP 代码 · 共 85 行
HPP
85 行
// Copyright (c) 2006 Xiaogang Zhang// Use, modification and distribution are subject to the// Boost Software License, Version 1.0. (See accompanying file// LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt)#ifndef BOOST_MATH_BESSEL_YN_HPP#define BOOST_MATH_BESSEL_YN_HPP#ifdef _MSC_VER#pragma once#endif#include <boost/math/special_functions/detail/bessel_y0.hpp>#include <boost/math/special_functions/detail/bessel_y1.hpp>#include <boost/math/policies/error_handling.hpp>// Bessel function of the second kind of integer order// Y_n(z) is the dominant solution, forward recurrence always OK (though unstable)namespace boost { namespace math { namespace detail{template <typename T, typename Policy>T bessel_yn(int n, T x, const Policy& pol){ T value, factor, current, prev; using namespace boost::math::tools; static const char* function = "boost::math::bessel_yn<%1%>(%1%,%1%)"; if ((x == 0) && (n == 0)) { return -policies::raise_overflow_error<T>(function, 0, pol); } if (x <= 0) { return policies::raise_domain_error<T>(function, "Got x = %1%, but x must be > 0, complex result not supported.", x, pol); } // // Reflection comes first: // if (n < 0) { factor = (n & 0x1) ? -1 : 1; // Y_{-n}(z) = (-1)^n Y_n(z) n = -n; } else { factor = 1; } if (n == 0) { value = bessel_y0(x, pol); } else if (n == 1) { value = factor * bessel_y1(x, pol); } else { prev = bessel_y0(x, pol); current = bessel_y1(x, pol); int k = 1; BOOST_ASSERT(k < n); do { value = 2 * k * current / x - prev; prev = current; current = value; ++k; } while(k < n); value *= factor; } return value;}}}} // namespaces#endif // BOOST_MATH_BESSEL_YN_HPP
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?