fused_procedure.hpp
来自「Boost provides free peer-reviewed portab」· HPP 代码 · 共 71 行
HPP
71 行
/*============================================================================= Copyright (c) 2006-2007 Tobias Schwinger Use modification and distribution are subject to the Boost Software License, Version 1.0. (See accompanying file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt).==============================================================================*/#if !defined(BOOST_FUSION_FUNCTIONAL_ADAPTER_FUSED_PROCEDURE_HPP_INCLUDED)#define BOOST_FUSION_FUNCTIONAL_ADAPTER_FUSED_PROCEDURE_HPP_INCLUDED#include <boost/type_traits/add_reference.hpp>#include <boost/fusion/functional/adapter/detail/access.hpp>#include <boost/fusion/functional/invocation/invoke_procedure.hpp>namespace boost { namespace fusion{ template <typename Function> class fused_procedure; //----- ---- --- -- - - - - template <typename Function> class fused_procedure { Function fnc_transformed; typedef typename detail::qf_c<Function>::type & func_const_fwd_t; typedef typename detail::qf<Function>::type & func_fwd_t; public: inline explicit fused_procedure(func_const_fwd_t f = Function()) : fnc_transformed(f) { } template <class Seq> inline void operator()(Seq const & s) const { fusion::invoke_procedure< func_const_fwd_t >(this->fnc_transformed,s); } template <class Seq> inline void operator()(Seq const & s) { fusion::invoke_procedure< func_fwd_t >(this->fnc_transformed,s); } template <class Seq> inline void operator()(Seq & s) const { fusion::invoke_procedure< func_const_fwd_t >(this->fnc_transformed,s); } template <class Seq> inline void operator()(Seq & s) { return fusion::invoke_procedure< func_fwd_t >(this->fnc_transformed,s); } typedef void result_type; };}}#endif
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