📄 sy2_1_2.cpp
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/**********************************************************************************/
#include "LStack.h"
void main()
{
Linkstack S;
Llist p,s,q;
Element e,element;
Status i;
int j,k,num;
void visit( Element n );
/********************************/
i = Init_Lstack( &S ); /*****建栈********/
if(i)
printf("建栈成功!\n");
printf( "S.stacksize=%d, S.base=%d, S.top=%d\n\n",S.stacksize, S.base, S.top );
/********************************/
i = Clear_Lstack( &S ); /****清空栈*******/
if(i)
printf("栈已空!\n");
printf( "S.stacksize=%d, S.base=%d, S.top=%d\n\n",S.stacksize, S.base, S.top );
/********************************/
i = LinkstackEmpty( S );
if(i)
printf("栈是空的!\n");
else
printf("栈不是空的!\n");
/********************************/
printf("Please input number of Stack element!\n");
scanf("%d",&num);
printf("Please input Stack Elemet!\n");
for( j = 1; j <= num; j++ ) /******插入元素*******/
{
scanf("%d",&element);
e = element;
i = Link_insert( &s,&e );
i = Push( &S, &s );
}
if(i)
printf("输入数据有效!\n");
else
printf("输入失败!\n");
/********************************/
i = LinkstackEmpty( S );
if(i)
printf("\n栈是空的!\n");
else
printf("\n栈不是空的!\n");
/********************************/
printf( "S.base=%d, S.top=%d, S.stacksize=%d\n\n",
S.base, S.top, S.stacksize );
/*********************************/
i = LinkstackGetTop( S, &e ); /***获得栈顶元素***/
if(i)
printf("\n获得栈顶元素成功!\n");
else
printf("\n获得栈顶元素不成功!\n");
printf( "Top=%d\n\n", e );
printf( "S.stacksize=%d\n\n",S.stacksize );
/**********************************/
for( j = 1; j <= num; j++ )
{
i = LinkstackPop( &S,&e ); /***删除栈顶元素***/
if(i)
printf("\n删除栈顶元素成功!\n");
else
printf("\n删除栈顶元素不成功!\n");
printf( "del=%d\n\n",e );
printf( "S.base=%d, S.top=%d, S.stacksize=%d\n\n",
S.base, S.top, S.stacksize );
}
/********************************/
i = LinkstackEmpty( S );
if(i)
printf("\n栈是空的!\n");
else
printf("\n栈不是空的!\n");
printf( "S.base=%d, S.top=%d, S.stacksize=%d\n\n",
S.base, S.top, S.stacksize );
/********************************/
i=DestoyLinkstack(&S);
if(i)
printf("\n栈已销毁!\n");
else
printf("\n失败!\n");
}
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