zlalsa.f.html
来自「famous linear algebra library (LAPACK) p」· HTML 代码 · 共 528 行 · 第 1/3 页
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</span><span class="comment">*</span><span class="comment"> .. Parameters ..
</span> DOUBLE PRECISION ZERO, ONE
PARAMETER ( ZERO = 0.0D0, ONE = 1.0D0 )
<span class="comment">*</span><span class="comment"> ..
</span><span class="comment">*</span><span class="comment"> .. Local Scalars ..
</span> INTEGER I, I1, IC, IM1, INODE, J, JCOL, JIMAG, JREAL,
$ JROW, LF, LL, LVL, LVL2, ND, NDB1, NDIML,
$ NDIMR, NL, NLF, NLP1, NLVL, NR, NRF, NRP1, SQRE
<span class="comment">*</span><span class="comment"> ..
</span><span class="comment">*</span><span class="comment"> .. External Subroutines ..
</span> EXTERNAL DGEMM, <a name="DLASDT.168"></a><a href="dlasdt.f.html#DLASDT.1">DLASDT</a>, <a name="XERBLA.168"></a><a href="xerbla.f.html#XERBLA.1">XERBLA</a>, ZCOPY, <a name="ZLALS0.168"></a><a href="zlals0.f.html#ZLALS0.1">ZLALS0</a>
<span class="comment">*</span><span class="comment"> ..
</span><span class="comment">*</span><span class="comment"> .. Intrinsic Functions ..
</span> INTRINSIC DBLE, DCMPLX, DIMAG
<span class="comment">*</span><span class="comment"> ..
</span><span class="comment">*</span><span class="comment"> .. Executable Statements ..
</span><span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> Test the input parameters.
</span><span class="comment">*</span><span class="comment">
</span> INFO = 0
<span class="comment">*</span><span class="comment">
</span> IF( ( ICOMPQ.LT.0 ) .OR. ( ICOMPQ.GT.1 ) ) THEN
INFO = -1
ELSE IF( SMLSIZ.LT.3 ) THEN
INFO = -2
ELSE IF( N.LT.SMLSIZ ) THEN
INFO = -3
ELSE IF( NRHS.LT.1 ) THEN
INFO = -4
ELSE IF( LDB.LT.N ) THEN
INFO = -6
ELSE IF( LDBX.LT.N ) THEN
INFO = -8
ELSE IF( LDU.LT.N ) THEN
INFO = -10
ELSE IF( LDGCOL.LT.N ) THEN
INFO = -19
END IF
IF( INFO.NE.0 ) THEN
CALL <a name="XERBLA.197"></a><a href="xerbla.f.html#XERBLA.1">XERBLA</a>( <span class="string">'<a name="ZLALSA.197"></a><a href="zlalsa.f.html#ZLALSA.1">ZLALSA</a>'</span>, -INFO )
RETURN
END IF
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> Book-keeping and setting up the computation tree.
</span><span class="comment">*</span><span class="comment">
</span> INODE = 1
NDIML = INODE + N
NDIMR = NDIML + N
<span class="comment">*</span><span class="comment">
</span> CALL <a name="DLASDT.207"></a><a href="dlasdt.f.html#DLASDT.1">DLASDT</a>( N, NLVL, ND, IWORK( INODE ), IWORK( NDIML ),
$ IWORK( NDIMR ), SMLSIZ )
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> The following code applies back the left singular vector factors.
</span><span class="comment">*</span><span class="comment"> For applying back the right singular vector factors, go to 170.
</span><span class="comment">*</span><span class="comment">
</span> IF( ICOMPQ.EQ.1 ) THEN
GO TO 170
END IF
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> The nodes on the bottom level of the tree were solved
</span><span class="comment">*</span><span class="comment"> by <a name="DLASDQ.218"></a><a href="dlasdq.f.html#DLASDQ.1">DLASDQ</a>. The corresponding left and right singular vector
</span><span class="comment">*</span><span class="comment"> matrices are in explicit form. First apply back the left
</span><span class="comment">*</span><span class="comment"> singular vector matrices.
</span><span class="comment">*</span><span class="comment">
</span> NDB1 = ( ND+1 ) / 2
DO 130 I = NDB1, ND
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> IC : center row of each node
</span><span class="comment">*</span><span class="comment"> NL : number of rows of left subproblem
</span><span class="comment">*</span><span class="comment"> NR : number of rows of right subproblem
</span><span class="comment">*</span><span class="comment"> NLF: starting row of the left subproblem
</span><span class="comment">*</span><span class="comment"> NRF: starting row of the right subproblem
</span><span class="comment">*</span><span class="comment">
</span> I1 = I - 1
IC = IWORK( INODE+I1 )
NL = IWORK( NDIML+I1 )
NR = IWORK( NDIMR+I1 )
NLF = IC - NL
NRF = IC + 1
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> Since B and BX are complex, the following call to DGEMM
</span><span class="comment">*</span><span class="comment"> is performed in two steps (real and imaginary parts).
</span><span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> CALL DGEMM( 'T', 'N', NL, NRHS, NL, ONE, U( NLF, 1 ), LDU,
</span><span class="comment">*</span><span class="comment"> $ B( NLF, 1 ), LDB, ZERO, BX( NLF, 1 ), LDBX )
</span><span class="comment">*</span><span class="comment">
</span> J = NL*NRHS*2
DO 20 JCOL = 1, NRHS
DO 10 JROW = NLF, NLF + NL - 1
J = J + 1
RWORK( J ) = DBLE( B( JROW, JCOL ) )
10 CONTINUE
20 CONTINUE
CALL DGEMM( <span class="string">'T'</span>, <span class="string">'N'</span>, NL, NRHS, NL, ONE, U( NLF, 1 ), LDU,
$ RWORK( 1+NL*NRHS*2 ), NL, ZERO, RWORK( 1 ), NL )
J = NL*NRHS*2
DO 40 JCOL = 1, NRHS
DO 30 JROW = NLF, NLF + NL - 1
J = J + 1
RWORK( J ) = DIMAG( B( JROW, JCOL ) )
30 CONTINUE
40 CONTINUE
CALL DGEMM( <span class="string">'T'</span>, <span class="string">'N'</span>, NL, NRHS, NL, ONE, U( NLF, 1 ), LDU,
$ RWORK( 1+NL*NRHS*2 ), NL, ZERO, RWORK( 1+NL*NRHS ),
$ NL )
JREAL = 0
JIMAG = NL*NRHS
DO 60 JCOL = 1, NRHS
DO 50 JROW = NLF, NLF + NL - 1
JREAL = JREAL + 1
JIMAG = JIMAG + 1
BX( JROW, JCOL ) = DCMPLX( RWORK( JREAL ),
$ RWORK( JIMAG ) )
50 CONTINUE
60 CONTINUE
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> Since B and BX are complex, the following call to DGEMM
</span><span class="comment">*</span><span class="comment"> is performed in two steps (real and imaginary parts).
</span><span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> CALL DGEMM( 'T', 'N', NR, NRHS, NR, ONE, U( NRF, 1 ), LDU,
</span><span class="comment">*</span><span class="comment"> $ B( NRF, 1 ), LDB, ZERO, BX( NRF, 1 ), LDBX )
</span><span class="comment">*</span><span class="comment">
</span> J = NR*NRHS*2
DO 80 JCOL = 1, NRHS
DO 70 JROW = NRF, NRF + NR - 1
J = J + 1
RWORK( J ) = DBLE( B( JROW, JCOL ) )
70 CONTINUE
80 CONTINUE
CALL DGEMM( <span class="string">'T'</span>, <span class="string">'N'</span>, NR, NRHS, NR, ONE, U( NRF, 1 ), LDU,
$ RWORK( 1+NR*NRHS*2 ), NR, ZERO, RWORK( 1 ), NR )
J = NR*NRHS*2
DO 100 JCOL = 1, NRHS
DO 90 JROW = NRF, NRF + NR - 1
J = J + 1
RWORK( J ) = DIMAG( B( JROW, JCOL ) )
90 CONTINUE
100 CONTINUE
CALL DGEMM( <span class="string">'T'</span>, <span class="string">'N'</span>, NR, NRHS, NR, ONE, U( NRF, 1 ), LDU,
$ RWORK( 1+NR*NRHS*2 ), NR, ZERO, RWORK( 1+NR*NRHS ),
$ NR )
JREAL = 0
JIMAG = NR*NRHS
DO 120 JCOL = 1, NRHS
DO 110 JROW = NRF, NRF + NR - 1
JREAL = JREAL + 1
JIMAG = JIMAG + 1
BX( JROW, JCOL ) = DCMPLX( RWORK( JREAL ),
$ RWORK( JIMAG ) )
110 CONTINUE
120 CONTINUE
<span class="comment">*</span><span class="comment">
</span> 130 CONTINUE
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> Next copy the rows of B that correspond to unchanged rows
</span><span class="comment">*</span><span class="comment"> in the bidiagonal matrix to BX.
</span><span class="comment">*</span><span class="comment">
</span> DO 140 I = 1, ND
IC = IWORK( INODE+I-1 )
CALL ZCOPY( NRHS, B( IC, 1 ), LDB, BX( IC, 1 ), LDBX )
140 CONTINUE
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> Finally go through the left singular vector matrices of all
</span><span class="comment">*</span><span class="comment"> the other subproblems bottom-up on the tree.
</span><span class="comment">*</span><span class="comment">
</span> J = 2**NLVL
SQRE = 0
<span class="comment">*</span><span class="comment">
</span> DO 160 LVL = NLVL, 1, -1
LVL2 = 2*LVL - 1
<span class="comment">*</span><span class="comment">
</span><span class="comment">*</span><span class="comment"> find the first node LF and last node LL on
</span><span class="comment">*</span><span class="comment"> the current level LVL
</span><span class="comment">*</span><span class="comment">
</span> IF( LVL.EQ.1 ) THEN
LF = 1
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