minmax-1.c

来自「用于进行gcc测试」· C语言 代码 · 共 84 行

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/* { dg-do run } *//* { dg-options "-fdump-tree-original" } *//* Check that MIN-MAX and MAX-MIN combinations are folded.  */extern void abort (void);#define MIN(a,b) ((a) < (b) ? (a) : (b))#define MAX(a,b) ((a) > (b) ? (a) : (b))int f1(int a, int b){   return MIN (MAX (a, b), b); /* == b */}int f2(int a, int b){   return MAX (MIN (a, b), b); /* == b */}int f3(int a, int b){   return MIN (MAX (b, a), b); /* == b */}int f4(int a, int b){   return MAX (MIN (b, a), b); /* == b */}int g1(int a, int b){   return MIN (a, MAX (a, b)); /* == a */}int g2(int a, int b){   return MAX (a, MIN (a, b)); /* == a */}int g3(int a, int b){   return MIN (a, MAX (b, a)); /* == a */}int g4(int a, int b){   return MAX (a, MIN (b, a)); /* == a */}int main(void){  if (f1 (1, 2) != 2)    abort ();  if (f2 (1, 2) != 2)    abort ();  if (f3 (1, 2) != 2)    abort ();  if (f4 (1, 2) != 2)    abort ();  if (g1 (1, 2) != 1)    abort ();  if (g2 (1, 2) != 1)    abort ();  if (g3 (1, 2) != 1)    abort ();  if (g4 (1, 2) != 1)    abort ();  return 0;}/* { dg-final { scan-tree-dump-times "MIN_EXPR" 0 "original"} } *//* { dg-final { scan-tree-dump-times "MAX_EXPR" 0 "original"} } *//* { dg-final { cleanup-tree-dump "original" } } */

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