section-anchors-vect-69.c
来自「用于进行gcc测试」· C语言 代码 · 共 121 行
C
121 行
/* { dg-require-effective-target section_anchors } */#include <stdarg.h>#include "tree-vect.h"#define N 32struct s{ int m; int n[N][N][N];};struct s2{ int m; int n[N-1][N-1][N-1];};struct test1{ struct s a; /* array a.n is unaligned */ int b; int c; struct s e; /* array e.n is aligned */};struct test2{ struct s2 a; /* array a.n is unaligned */ int b; int c; struct s2 e; /* array e.n is aligned */};struct test1 tmp1[4];struct test2 tmp2[4];int main1 (){ int i,j; /* 1. unaligned */ for (i = 0; i < N; i++) { tmp1[2].a.n[1][2][i] = 5; } /* check results: */ for (i = 0; i <N; i++) { if (tmp1[2].a.n[1][2][i] != 5) abort (); } /* 2. aligned */ for (i = 3; i < N-1; i++) { tmp1[2].a.n[1][2][i] = 6; } /* check results: */ for (i = 3; i < N-1; i++) { if (tmp1[2].a.n[1][2][i] != 6) abort (); } /* 3. aligned */ for (i = 0; i < N; i++) { for (j = 0; j < N; j++) { tmp1[2].e.n[1][i][j] = 8; } } /* check results: */ for (i = 0; i < N; i++) { for (j = 0; j < N; j++) { if (tmp1[2].e.n[1][i][j] != 8) abort (); } } /* 4. unaligned */ for (i = 0; i < N-4; i++) { for (j = 0; j < N-4; j++) { tmp2[2].e.n[1][i][j] = 8; } } /* check results: */ for (i = 0; i < N-4; i++) { for (j = 0; j < N-4; j++) { if (tmp2[2].e.n[1][i][j] != 8) abort (); } } return 0;}int main (void){ check_vect (); return main1 ();} /* { dg-final { scan-tree-dump-times "vectorized 4 loops" 1 "vect" { target vect_int } } } *//* { dg-final { scan-tree-dump-times "Vectorizing an unaligned access" 0 "vect" } } *//* Alignment forced using versioning until the pass that increases alignment is extended to handle structs. *//* { dg-final { scan-tree-dump-times "Alignment of access forced using peeling" 4 "vect" { target {vect_int && vector_alignment_reachable } } } } *//* { dg-final { scan-tree-dump-times "Alignment of access forced using versioning" 4 "vect" { target {vect_int && {! vector_alignment_reachable} } } } } *//* { dg-final { cleanup-tree-dump "vect" } } */
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?