copysign1.c

来自「用于进行gcc测试」· C语言 代码 · 共 77 行

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#include <string.h>#include <stdlib.h>#include <float.h>#define fpsizeoff	sizeof(float)#define fpsizeof	sizeof(double)#define fpsizeofl	sizeof(long double)/* Work around the fact that with the Intel double-extended precision,   we've got a 10 byte type stuffed into some amount of padding.  And   the fact that -ffloat-store is going to stuff this value temporarily   into some bit of stack frame that we've no control over and can't zero.  */#if LDBL_MANT_DIG == 64# if defined(__i386__) || defined(__x86_64__) || defined (__ia64__)#  undef fpsizeofl#  define fpsizeofl	10# endif#endif/* Work around the fact that the sign of the second double in the IBM   double-double format is not strictly specified when it contains a zero.   For instance, -0.0L can be represented with either (-0.0, +0.0) or   (-0.0, -0.0).  The former is what we'll get from the compiler when it   builds constants; the later is what we'll get from the negation operator   at runtime.  *//* ??? This hack only works for big-endian, which is fortunately true for   all of AIX, Darwin, and Irix.  */#if LDBL_MANT_DIG == 106# undef fpsizeofl# define fpsizeofl	sizeof(double)#endif#define TEST(TYPE, EXT)						\TYPE c##EXT (TYPE x, TYPE y)					\{								\  return __builtin_copysign##EXT (x, y);			\}								\								\struct D##EXT { TYPE x, y, z; };				\								\static const struct D##EXT T##EXT[] = {				\  { 1.0, 2.0, 1.0 },						\  { 1.0, -2.0, -1.0 },						\  { -1.0, -2.0, -1.0 },						\  { 0.0, -2.0, -0.0 },						\  { -0.0, -2.0, -0.0 },						\  { -0.0, 2.0, 0.0 },						\  { __builtin_inf##EXT (), -0.0, -__builtin_inf##EXT () },	\  { -__builtin_nan##EXT (""), __builtin_inf##EXT (),		\    __builtin_nan##EXT ("") }					\};								\								\void test##EXT (void)						\{								\  int i, n = sizeof (T##EXT) / sizeof (T##EXT[0]);		\  TYPE r;							\  for (i = 0; i < n; ++i)					\    {								\      r = c##EXT (T##EXT[i].x, T##EXT[i].y);			\      if (memcmp (&r, &T##EXT[i].z, fpsizeof##EXT) != 0)	\	abort ();						\    }								\}TEST(float, f)TEST(double, )TEST(long double, l)int main(){  testf();  test();  testl();  return 0;}

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