copysign1.c
来自「用于进行gcc测试」· C语言 代码 · 共 77 行
C
77 行
#include <string.h>#include <stdlib.h>#include <float.h>#define fpsizeoff sizeof(float)#define fpsizeof sizeof(double)#define fpsizeofl sizeof(long double)/* Work around the fact that with the Intel double-extended precision, we've got a 10 byte type stuffed into some amount of padding. And the fact that -ffloat-store is going to stuff this value temporarily into some bit of stack frame that we've no control over and can't zero. */#if LDBL_MANT_DIG == 64# if defined(__i386__) || defined(__x86_64__) || defined (__ia64__)# undef fpsizeofl# define fpsizeofl 10# endif#endif/* Work around the fact that the sign of the second double in the IBM double-double format is not strictly specified when it contains a zero. For instance, -0.0L can be represented with either (-0.0, +0.0) or (-0.0, -0.0). The former is what we'll get from the compiler when it builds constants; the later is what we'll get from the negation operator at runtime. *//* ??? This hack only works for big-endian, which is fortunately true for all of AIX, Darwin, and Irix. */#if LDBL_MANT_DIG == 106# undef fpsizeofl# define fpsizeofl sizeof(double)#endif#define TEST(TYPE, EXT) \TYPE c##EXT (TYPE x, TYPE y) \{ \ return __builtin_copysign##EXT (x, y); \} \ \struct D##EXT { TYPE x, y, z; }; \ \static const struct D##EXT T##EXT[] = { \ { 1.0, 2.0, 1.0 }, \ { 1.0, -2.0, -1.0 }, \ { -1.0, -2.0, -1.0 }, \ { 0.0, -2.0, -0.0 }, \ { -0.0, -2.0, -0.0 }, \ { -0.0, 2.0, 0.0 }, \ { __builtin_inf##EXT (), -0.0, -__builtin_inf##EXT () }, \ { -__builtin_nan##EXT (""), __builtin_inf##EXT (), \ __builtin_nan##EXT ("") } \}; \ \void test##EXT (void) \{ \ int i, n = sizeof (T##EXT) / sizeof (T##EXT[0]); \ TYPE r; \ for (i = 0; i < n; ++i) \ { \ r = c##EXT (T##EXT[i].x, T##EXT[i].y); \ if (memcmp (&r, &T##EXT[i].z, fpsizeof##EXT) != 0) \ abort (); \ } \}TEST(float, f)TEST(double, )TEST(long double, l)int main(){ testf(); test(); testl(); return 0;}
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?