20051113-1.c

来自「用于进行gcc测试」· C语言 代码 · 共 72 行

C
72
字号
extern void *malloc(__SIZE_TYPE__);extern void *memset(void *, int, __SIZE_TYPE__);typedef struct{  short a;    unsigned short b;  unsigned short c;  unsigned long long Count;  long long Count2;} __attribute__((packed)) Struct1;typedef struct{  short a;  unsigned short b;  unsigned short c;  unsigned long long d;  long long e;  long long f;} __attribute__((packed)) Struct2;typedef union{  Struct1 a;  Struct2 b;} Union;typedef struct{  int Count;  Union List[0];} __attribute__((packed)) Struct3;unsigned long long Sum (Struct3 *instrs) __attribute__((noinline));unsigned long long Sum (Struct3 *instrs){    unsigned long long  count = 0;    int     i;        for (i = 0; i < instrs->Count; i++) {        count += instrs->List[i].a.Count;    }    return count;}long long Sum2 (Struct3 *instrs) __attribute__((noinline));long long Sum2 (Struct3 *instrs){    long long  count = 0;    int     i;        for (i = 0; i < instrs->Count; i++) {        count += instrs->List[i].a.Count2;    }    return count;}main() {  Struct3 *p = malloc (sizeof (int) + 3 * sizeof(Union));  memset(p, 0, sizeof(int) + 3*sizeof(Union));  p->Count = 3;  p->List[0].a.Count = 555;  p->List[1].a.Count = 999;  p->List[2].a.Count = 0x101010101ULL;  p->List[0].a.Count2 = 555;  p->List[1].a.Count2 = 999;  p->List[2].a.Count2 = 0x101010101LL;  if (Sum(p) != 555 + 999 + 0x101010101ULL)    abort();  if (Sum2(p) != 555 + 999 + 0x101010101LL)    abort();  return 0;}

⌨️ 快捷键说明

复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?