c35503a.ada

来自「用于进行gcc测试」· ADA 代码 · 共 81 行

ADA
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-- C35503A.ADA--                             Grant of Unlimited Rights----     Under contracts F33600-87-D-0337, F33600-84-D-0280, MDA903-79-C-0687,--     F08630-91-C-0015, and DCA100-97-D-0025, the U.S. Government obtained --     unlimited rights in the software and documentation contained herein.--     Unlimited rights are defined in DFAR 252.227-7013(a)(19).  By making --     this public release, the Government intends to confer upon all --     recipients unlimited rights  equal to those held by the Government.  --     These rights include rights to use, duplicate, release or disclose the --     released technical data and computer software in whole or in part, in --     any manner and for any purpose whatsoever, and to have or permit others --     to do so.----                                    DISCLAIMER----     ALL MATERIALS OR INFORMATION HEREIN RELEASED, MADE AVAILABLE OR--     DISCLOSED ARE AS IS.  THE GOVERNMENT MAKES NO EXPRESS OR IMPLIED --     WARRANTY AS TO ANY MATTER WHATSOEVER, INCLUDING THE CONDITIONS OF THE--     SOFTWARE, DOCUMENTATION OR OTHER INFORMATION RELEASED, MADE AVAILABLE --     OR DISCLOSED, OR THE OWNERSHIP, MERCHANTABILITY, OR FITNESS FOR A--     PARTICULAR PURPOSE OF SAID MATERIAL.--*-- CHECK THAT 'WIDTH' YIELDS THE CORRECT RESULT WHEN THE PREFIX IS AN -- INTEGER TYPE.-- RJW 3/12/86WITH REPORT; USE REPORT;PROCEDURE C35503A ISBEGIN     TEST ("C35503A", "CHECK THAT 'WIDTH' YIELDS THE CORRECT " &                      "RESULT WHEN THE PREFIX IS AN INTEGER TYPE" );     DECLARE          SUBTYPE SINTEGER IS INTEGER;                    TYPE INT IS RANGE -1000 .. 1000;          TYPE INT2 IS NEW INT RANGE 1E2 .. 1E2;          SUBTYPE SINT1 IS INT RANGE 00000 .. 100;          SUBTYPE SINT2 IS INT RANGE 16#E#E1 .. 2#1111_1111#;          SUBTYPE SINT3 IS INT RANGE -100 .. 9;          SUBTYPE NOINT IS INT RANGE 1 .. -1;     BEGIN          IF IDENT_INT(SINTEGER'WIDTH) /= INTEGER'WIDTH THEN               FAILED ( "WRONG WIDTH FOR 'SINTEGER'" );          END IF;          IF IDENT_INT(INT'WIDTH) /= 5 THEN               FAILED ( "WRONG WIDTH FOR 'INT'" );          END IF;          IF IDENT_INT(INT2'WIDTH) /= 4 THEN               FAILED ( "WRONG WIDTH FOR 'INT2'");          END IF;          IF IDENT_INT(SINT1'WIDTH) /= 4 THEN                FAILED ( "WRONG WIDTH FOR 'SINT1'" );          END IF;          IF IDENT_INT(SINT2'WIDTH) /= 4 THEN                FAILED ( "WRONG WIDTH FOR 'SINT2'" );          END IF;          IF IDENT_INT(SINT3'WIDTH) /= 4 THEN               FAILED ( "WRONG WIDTH FOR 'SINT3'" );          END IF;          IF IDENT_INT(NOINT'WIDTH) /= 0 THEN               FAILED ( "WRONG WIDTH FOR 'NOINT'" );          END IF;     END;     RESULT;END C35503A;

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