c960002.a

来自「用于进行gcc测试」· A 代码 · 共 172 行

A
172
字号
-- C960002.A ----                             Grant of Unlimited Rights----     Under contracts F33600-87-D-0337, F33600-84-D-0280, MDA903-79-C-0687,--     F08630-91-C-0015, and DCA100-97-D-0025, the U.S. Government obtained --     unlimited rights in the software and documentation contained herein.--     Unlimited rights are defined in DFAR 252.227-7013(a)(19).  By making --     this public release, the Government intends to confer upon all --     recipients unlimited rights  equal to those held by the Government.  --     These rights include rights to use, duplicate, release or disclose the --     released technical data and computer software in whole or in part, in --     any manner and for any purpose whatsoever, and to have or permit others --     to do so.----                                    DISCLAIMER----     ALL MATERIALS OR INFORMATION HEREIN RELEASED, MADE AVAILABLE OR--     DISCLOSED ARE AS IS.  THE GOVERNMENT MAKES NO EXPRESS OR IMPLIED --     WARRANTY AS TO ANY MATTER WHATSOEVER, INCLUDING THE CONDITIONS OF THE--     SOFTWARE, DOCUMENTATION OR OTHER INFORMATION RELEASED, MADE AVAILABLE --     OR DISCLOSED, OR THE OWNERSHIP, MERCHANTABILITY, OR FITNESS FOR A--     PARTICULAR PURPOSE OF SAID MATERIAL.--*---- OBJECTIVE:--      Check that the simple "delay until" when the request time is "now" and--      also some time already in the past is obeyed and returns immediately---- TEST DESCRIPTION:--      Simulate a task that sends a "pulse" at regular intervals.  The Delay--      Until statement is used to avoid accumulated drift.  In this test--      three simple situations simulating the start of drift are used:  the--      next pulse being called for at the normal time, the next pulse being--      called for at exactly the current time and then at some time which has--      already past.  We assume the delay is within a While Loop and, to--      simplify the test, we "unfold" the While Loop and  execute the Delays--      in a serial fashion.  This loop is shown in test C960001.--      It is not possible to test the actual immediacy of the expiration. We--      can only check that it returns in a "reasonable" time.  In this case--      we check that it expires before the next "pulse" should have been --      issued.------ CHANGE HISTORY:--      06 Dec 94   SAIC    ACVC 2.0----!with Report;with ImpDef;with Ada.Calendar;with System;                                                procedure C960002 isbegin   Report.Test ("C960002", "Simple Delay Until with requested time being" &                        " ""now"" and time already in the past");   declare  -- To get the Report.Result after all has completed      function "+" (Left : Ada.Calendar.Time; Right: Duration)                            return Ada.Calendar.Time renames Ada.Calendar."+";      function "-" (Left : Ada.Calendar.Time; Right: Duration)                            return Ada.Calendar.Time renames Ada.Calendar."-";      function "-" (Left, Right : Ada.Calendar.Time)                            return duration      renames Ada.Calendar."-";      function ">" (Left, Right : Ada.Calendar.Time)                            return Boolean       renames Ada.Calendar.">";            task Pulse_Task is          entry Trigger;      end Pulse_Task;         -- Task to synchronize all qualified receivers.        -- The entry Trigger starts the synchronization.       --      task body Pulse_Task is         Pulse_Time       : Ada.Calendar.Time;         Pulse_Time_Delta : constant duration := ImpDef.Clear_Ready_Queue;          TC_Time_Back     : Ada.Calendar.Time;         -- This routine transmits a synchronizing "pulse" to         -- all receivers         procedure Pulse is         begin            null;  -- Stub            Report.Comment (".......PULSE........");               end Pulse;               begin         accept Trigger;         Pulse;         ---------------         -- normal calculation for "next"         Pulse_Time := Ada.Calendar.Clock + Pulse_Time_Delta;          -- TC:  unfold the "while" loop in C960001.  Four passes through          -- the loop are shown            delay until Pulse_Time;              Pulse;            ---------------            -- TC: the normal calculation for "next" would be            -- Pulse_Time := Pulse_Time + Pulse_Time_Delta;            -- Instead of this normal pulse time calculation simulate            -- the new pulse time to be exactly "now"  (or, as exactly as             -- we can)            Pulse_Time := Ada.Calendar.Clock;             delay until  Ada.Calendar.Clock;             TC_Time_Back := Ada.Calendar.Clock;            -- Now check for reasonableness            if TC_Time_Back > Pulse_Time + Pulse_Time_Delta then               Report.Failed                      ("""Now"" delayed for more than Pulse_Time_Delta - A");            end if;            Pulse;            ---------------            -- normal calculation for "next" would be            Pulse_Time := Pulse_Time + Pulse_Time_Delta;            -- TC: Instead of this, simulate the new calculated pulse time            -- being already past            Pulse_Time := Ada.Calendar.Clock - System.Tick;            delay until Pulse_Time;            TC_Time_Back := Ada.Calendar.Clock;            -- Now check for reasonableness            if TC_Time_Back > Pulse_Time + Pulse_Time_Delta then               Report.Failed                      ("""Now"" delayed for more than Pulse_Time_Delta - B");            end if;            Pulse;            ---------------            -- normal calculation for "next"            Pulse_Time := Pulse_Time + Pulse_Time_Delta;            -- Now simulate getting back into synch            delay until Pulse_Time;            Pulse;            ---------------         -- This would be the end of the "while" loop      exception         when others =>                Report.Failed ("Unexpected exception in Pulse_Task");      end Pulse_Task;   begin -- declare      Pulse_Task.Trigger;      -- Start test                               end; -- declare   Report.Result;end C960002;

⌨️ 快捷键说明

复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?