📄 exa3_10.m
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finverse(sym('1/x')) % the inverse of 1/x is 1/x since ‘1/(1/x)=x’
finverse(sym('x^2')) % g(x^2)=x has more than one solution
finverse(sym('a*x+b')) % find the solution to ‘g(f(x))=x’
finverse(sym('a*b+c*d-a*z'),sym('a')) % find the solution to ‘g(f(a))=a’
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