count.c

来自「unix环境下实现的cmm语言编译器」· C语言 代码 · 共 41 行

/*count.c: 统计各个数字、空白及其它字符的次数*/
int puts(char *);
int printf(char *fmt, int);
int getchar();
int main(void)
{
	int c, i, nwhite, nother;
	int ndigit[10];
	
	nwhite = nother = 0;
	i = 0;
	while (i < 10) {
		ndigit[i] = 0;
		i = i + 1;
	}
	
	while ((c = getchar()) != -1) {
		if (c >= '0') 
			if (c <= '9') {
				ndigit[c-'0'] = ndigit[c-'0'] + 1;
				continue;
			}
		if (c == ' ')
			nwhite = nwhite + 1;
		else if (c == '\n')
			nwhite = nwhite + 1;
		else if (c == '\t')
			nwhite = nwhite + 1;
		else
			nother = nother + 1;
	}
	puts("digits =");
	i = 0;
	while (i < 10) {
		printf(" %d", ndigit[i]);
		i = i + 1;
	}
	printf(",white space = %d", nwhite);
	printf(",other = %d\n",nother);
}