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<p>// Permuted Choice 2 (PC-2)<br>const static char PC2_Table[48] =<br>{<br> 14, 17, 11, 24, 1, 5,<br> 3, 28, 15, 6, 21, 10,<br> 23, 19, 12, 4, 26, 8,<br> 16, 7, 27, 20, 13, 2,<br> 41, 52, 31, 37, 47, 55,<br> 30, 40, 51, 45, 33, 48,<br> 44, 49, 39, 56, 34, 53,<br> 46, 42, 50, 36, 29, 32<br>};</p><p>// Initial Permutation (IP)<br>const static char IP_Table[64] =<br>{<br> 58, 50, 42, 34, 26, 18, 10, 2,<br> 60, 52, 44, 36, 28, 20, 12, 4,<br> 62, 54, 46, 38, 30, 22, 14, 6,<br> 64, 56, 48, 40, 32, 24, 16, 8,<br> 57, 49, 41, 33, 25, 17, 9, 1,<br> 59, 51, 43, 35, 27, 19, 11, 3,<br> 61, 53, 45, 37, 29, 21, 13, 5,<br> 63, 55, 47, 39, 31, 23, 15, 7<br>};</p><p>// Expansion (E)<br>static const char E_Table[48] =<br>{<br> 32, 1, 2, 3, 4, 5, <br> 4, 5, 6, 7, 8, 9,<br> 8, 9, 10, 11, 12, 13, <br> 12, 13, 14, 15, 16, 17,<br> 16, 17, 18, 19, 20, 21, <br> 20, 21, 22, 23, 24, 25,<br> 24, 25, 26, 27, 28, 29, <br> 28, 29, 30, 31, 32, 1<br>};</p><p>// The (in)famous S-boxes<br>const static char S_Box[8][4][16] =<br>{<br> {<br> // S1 <br> {14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7},<br> { 0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8},<br> { 4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0},<br> {15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13}<br> },<br> {<br> // S2 <br> {15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10},<br> { 3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5},<br> { 0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15},<br> {13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9}<br> },<br> {<br> // S3 <br> {10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8},<br> {13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1},<br> {13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7},<br> { 1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12}<br> },<br> {<br> // S4 <br> { 7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15},<br> {13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9},<br> {10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4},<br> { 3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14}<br> },<br> {<br> // S5 <br> { 2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9},<br> {14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6},<br> { 4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14},<br> {11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3}<br> },<br> {<br> // S6 <br> {12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11},<br> {10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8},<br> { 9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6},<br> { 4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13}<br> },<br> {<br> // S7 <br> { 4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1},<br> {13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6},<br> { 1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2},<br> { 6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12}<br> },<br> {<br> // S8 <br> {13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7},<br> { 1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2},<br> { 7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8},<br> { 2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11}<br> }<br>};</p><p>// Permutation P<br>const static char P_Table[32] =<br>{<br> 16, 7, 20, 21, <br> 29, 12, 28, 17,<br> 1, 15, 23, 26,<br> 5, 18, 31, 10,<br> 2, 8, 24, 14,<br> 32, 27, 3, 9,<br> 19, 13, 30, 6,<br> 22, 11, 4, 25<br>};</p><p>// Final Permutation (IP**-1)<br>const static char IPR_Table[64] =<br>{<br> 40, 8, 48, 16, 56, 24, 64, 32,<br> 39, 7, 47, 15, 55, 23, 63, 31,<br> 38, 6, 46, 14, 54, 22, 62, 30,<br> 37, 5, 45, 13, 53, 21, 61, 29,<br> 36, 4, 44, 12, 52, 20, 60, 28,<br> 35, 3, 43, 11, 51, 19, 59, 27,<br> 34, 2, 42, 10, 50, 18, 58, 26,<br> 33, 1, 41, 9, 49, 17, 57, 25<br>};</p><p>// 主函数<br>void Des_SetKey(const char Key[8]);<br>void Des_Run(char Out[8], char In[8], bool Type);</p><p>// 功能函数<br>static void F_func(bool In[32], const bool Ki[48]); // f 函数<br>static void S_func(bool Out[32], const bool In[48]); // S 盒代替<br>static void Transform(bool *Out, bool *In, const char *Table, int len); // 变换<br>static void Xor(bool *InA, const bool *InB, int len); // 异或<br>static void RotateL(bool *In, int len, int loop); // 循环左移<br>static void ByteToBit(bool *Out, const char *In, int bits); // 字节组转换成位组<br>static void BitToByte(char *Out, const bool *In, int bits); // 位组转换成字节组</p><p>// 测试用<br>static void printHex( char *cmd, int len );<br>static void printArray( const char *In, int len );</p><p>int main(int argc, char *argv[])<br>{<br> char key[12]={1,2,3,4,5,6,7,8};<br> char str[12]="YOKO LA!";<br> char str2[12];<br> <br> //printArray( PC2_Table, sizeof(PC2_Table)/sizeof(PC2_Table[0]) );<br> <br> printf("Before encrypting: ");<br> puts(str);</p><p> Des_SetKey(key);</p><p> memset(str2, 0, sizeof(str2));<br> Des_Run(str2, str, ENCRYPT);<br> printf("After encrypting: ");<br> printHex( str2, 8 );</p><p> memset(str, 0, sizeof(str));<br> printf("After decrypting: ");<br> Des_Run(str, str2, DECRYPT);<br> puts(str);<br> <br> return 0;<br>}</p><p>// == 1. Process the key ==<br>void Des_SetKey(const char Key[8])<br>{<br> int i;<br> static bool K[64], *KL = &K[0], *KR = &K[28];<br> <br> ByteToBit(K, Key, 64);<br> <br> Transform(K, K, PC1_Table, 56);<br> <br> // 1.2.3 Calculate the 16 sub keys. Start with i = 1. <br> for(i=0; i<16; i++)<br> {<br> // 1.2.3.1 Perform one or two circular left shifts on both C[i-1] and D[i-1] to get C[i] and D[i], respectively. <br> RotateL(KL, 28, LOOP_Table[i]);<br> RotateL(KR, 28, LOOP_Table[i]);<br> <br> // 1.2.3.2 Permute the concatenation C[i]D[i] as indicated below. This will yield K[i], which is 48 bits long.<br> Transform(SubKey[i], K, PC2_Table, 48);<br> }<br>}</p><p>// == 2. Process a 64-bit data block ==<br>void Des_Run(char Out[8], char In[8], bool Type)<br>{<br> int i;<br> static bool M[64], tmp[32], *Li = &M[0], *Ri = &M[32];<br> <br> // 2.1 Get a 64-bit data block. If the block is shorter than 64 bits, it should be padded as appropriate for the application. <br> ByteToBit(M, In, 64);<br> <br> // 2.2 Perform the following permutation on the data block. <br> Transform(M, M, IP_Table, 64);<br> <br> //2.3 Split the block into two halves. The first 32 bits are called L[0], and the last 32 bits are called R[0]. <br> <br> if( Type == ENCRYPT )<br> {<br> // 2.4 Apply the 16 sub keys to the data block. Start with i = 1. <br> for(i=0; i<16; i++)<br> {<br> memcpy(tmp, Ri, 32);<br> <br> // R[i] = L[i-1] xor f(R[i-1], K[i])<br> F_func(Ri, SubKey[i]);<br> <br> // 2.4.6 Exclusive-or the resulting value with L[i-1].<br> // R[I]=P XOR L[I-1]<br> Xor(Ri, Li, 32);<br> <br> // L[i] = R[i-1]<br> memcpy(Li, tmp, 32);<br> <br> } //2.4.8 Loop back to 2.4.1 until K[16] has been applied. <br> }<br> else<br> {<br> // To decrypt, use the same process<br> // but just use the keys K[i] in reverse order<br> for(i=15; i>=0; i--)<br> {<br> memcpy(tmp, Li, 32);<br> F_func(Li, SubKey[i]);<br> Xor(Li, Ri, 32);<br> memcpy(Ri, tmp, 32);<br> }<br> }<br> <br> // 2.5 Perform the following permutation on the block R[16]L[16]. (Note that block R precedes block L this time.) <br> Transform(M, M, IPR_Table, 64);<br> <br> BitToByte(Out, M, 64);<br>}</p><p>void F_func(bool In[32], const bool Ki[48])<br>{<br> static bool MR[48];<br> <br> // 2.4.1 Expand the 32-bit R[i-1] into 48 bits according to the bit-selection function below. <br> Transform(MR, In, E_Table, 48);<br> <br> // 2.4.2 Exclusive-or E(R[i-1]) with K[i]. <br> Xor(MR, Ki, 48);<br> <br> // 2.4.4 Substitute the values found in the S-boxes for all B[j]. Start with j = 1. All values in the S-boxes should be considered 4 bits wide. <br> S_func(In, MR);<br> <br> // 2.4.5 Permute the concatenation of B[1] through B[8] as indicated below. <br> Transform(In, In, P_Table, 32);<br>}</p><p>void S_func(bool Out[32], const bool In[48])<br>{<br> char j,m,n;<br> <br> //2.4.3 Break E(R[i-1]) xor K[i] into eight 6-bit blocks. Bits 1-6 are B[1]... <br> for(j=0; j<8; j++,In+=6,Out+=4)<br> {<br> // 2.4.4.1 Take the 1st and 6th bits of B[j] together as a 2-bit value (call it m) indicating the row in S[j] to look in for the substitution. <br> m = (In[0]<<1) + In[5];<br> <br> // 2.4.4.2 Take the 2nd through 5th bits of B[j] together as a 4-bit value (call it n) indicating the column in S[j] to find the substitution.<br> n = (In[1]<<3) + (In[2]<<2) + (In[3]<<1) + In[4];<br> <br> // 2.4.4.3 Replace B[j] with S[j][m][n]. <br> ByteToBit(Out, &S_Box[(int)j][(int)m][(int)n], 4);<br> }<br>}</p><p>// -- Perform the permutation --<br>void Transform(bool *Out, bool *In, const char *Table, int len)<br>{<br> int i;<br> static bool tmp[256];<br> <br> for(i=0; i<len; i++)<br> {<br> tmp[i] = In[ Table[i]-1 ];<br> }<br> memcpy(Out, tmp, len);<br>}</p><p>// -- xor --<br>void Xor(bool *InA, const bool *InB, int len)<br>{<br> int i;<br> <br> for(i=0; i<len; i++)<br> {<br> InA[i] ^= InB[i];<br> }<br>}</p><p>// -- Perform one or two circular left shifts --<br>void RotateL(bool *In, int len, int loop)<br>{<br> static bool tmp[256]; // Sample:<br> // loop=2<br> memcpy(tmp, In, loop); // In=12345678 tmp=12<br> memcpy(In, In+loop, len-loop); // In=345678 <br> memcpy(In+len-loop, tmp, loop); // In=34567812<br>}</p><p>// Sample:<br>// In = [0x01]<br>// Out = [0x01] [0x00] [0x00] [0x00] [0x00] [0x00] [0x00] [0x00]<br>void ByteToBit(bool *Out, const char *In, int bits)<br>{<br> int i;<br> <br> for(i=0; i<bits; i++)<br> {<br> // In[i]的第N位右移N位并和0x01按位"与"运算(N=1~8)<br> Out[i] = (In[i/8]>>(i%8)) & 1;<br> }<br>}</p><p>void BitToByte(char *Out, const bool *In, int bits)<br>{<br> int i;<br> <br> memset(Out, 0, (bits+7)/8);<br> for(i=0; i<bits; i++)<br> {<br> Out[i/8] |= In[i]<<(i%8);<br> }<br>}</p><p>// 打印指定位置指定长度HEX值<br>static void printHex( char *cmd, int len )<br>{<br> int i;<br> <br> for(i=0; i<len; i++)<br> {<br> printf("[%02X]",(unsigned char)cmd[i]);<br> }<br> printf("\n");<br>}</p><p>// 打印数组测试用<br>static void printArray( const char *In, int len )<br>{<br> int i;<br> char tmp[256];<br> <br> memset(tmp, 0, sizeof(tmp));<br> <br> for( i=0; i<len; i++)<br> {<br> tmp[(int)In[i]]=In[i];<br> }<br> <br> for( i=0; i<len; i++)<br> {<br> printf("[%02d]",(unsigned char)tmp[i]);<br> }<br> printf("\n");<br>}<br> <br> <br></p></div></td></tr></table><br><div class="opt"><a href="/sgb44/blog/category/Abc" title="查看该分类中所有文章">类别:Abc</a> | <a title="将此文章添加到百度搜藏" href="http://cang.baidu.com/do/add" onClick="return addToFavor();" target="_blank">添加到搜藏</a> | 浏览(<span id="result"></span>) | <a href="#send">评论</a> (1)<script language="javascript">
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