test.m

利用矩阵分析的方法对线性方程组进行求解分析

%一个不能实现的GUI界面
%1
clf reset
H=axes('unit','normalized','position',[0,0,1,1],'visible','off');
set(gcf,'currentaxes',H);
str='\fontname{隶书}归一化系统的阶跃响应曲线';
text(0.12,0.93,str,'fontsize',13);
h_fig=get(H,'parent');
set(h_fig,'unit','normalized','position',[0.1,0.2,0.7,0.4]);
h_axes=axes('parent',h_flg,...
            'unit','normalized','position',[0.1,0.15,0.55,0.7],...
            'xlim',[0 15],'ylim',[0 1.8],'fontsize',8);
%2
h_text=uicontrol(h_fig,'style','text',...
                 'unit','normalized','position',[0.67,0.73,0.25,0.14],...
                 'horizontal','left','string',{'输入阻尼系数','zeta='});
h_edit=uicontrol(h_fig,'style','text',...
                 'unit','normalized','position',[0.67,0.59,0.25,0.14],...
                 'horizontal','left','callback',...
                 ['z=str2num(get(gcbo,''string''));',...
                     't=0:0.1:15;'...
                     'for k=1:length(z);',...
                     'y(:,k)=step(1,[1 2*z(k) 1],t);',...
                     'plot(t,y(:,k));',...
                     'if(length(z)>1),hold on,end,',...
                     'end;',...
                     'hold off,']);
%3
h_push1=uicontrol(h_fig,'style','push',...
                   'unit','normalized','position',[0.67,0.37,0.12,0.15],...
                   'string','grid on','callback','grid on');
               h_push2=uicontrol(h_fig,'style','push',...
                                  'unit','normalized','position',[0.67,0.15,0.12,0.15],...
                                      'string','grid off','callback','grid off');