dopt1.c

DSP培训 作业【源码】

int dopt1 (short a[] ,short b[],int N)
{
   int sum0 , sum1 ,sum ,i;
   
   sum0 =0 ; sum1 = 0 ;
   
   for (i =0 ; i < N ;i += 2)
     { sum0+= a[i] * b[i];
       sum1+= a[i+1] * b[i+1];
      }
    sum = sum0 + sum1; 
    return (sum); 
}