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📄 fqsmjs.frm

📁 用于空间插值的地理数据处理的趋势面分析
💻 FRM
字号:
VERSION 5.00
Begin VB.Form Form1 
   Caption         =   "Form1"
   ClientHeight    =   6630
   ClientLeft      =   60
   ClientTop       =   450
   ClientWidth     =   2010
   LinkTopic       =   "Form1"
   ScaleHeight     =   6630
   ScaleWidth      =   2010
   StartUpPosition =   3  '窗口缺省
   Begin VB.CommandButton Command6 
      Caption         =   "显著性检验"
      Height          =   375
      Left            =   360
      TabIndex        =   5
      Top             =   5760
      Width           =   1335
   End
   Begin VB.CommandButton Command5 
      Caption         =   "拟合度检验"
      Height          =   375
      Left            =   360
      TabIndex        =   4
      Top             =   4680
      Width           =   1335
   End
   Begin VB.CommandButton Command4 
      Caption         =   "拟合计算"
      Height          =   375
      Left            =   360
      TabIndex        =   3
      Top             =   2520
      Width           =   1335
   End
   Begin VB.CommandButton Command3 
      Caption         =   "数据输出"
      Height          =   375
      Left            =   360
      TabIndex        =   2
      Top             =   3600
      Width           =   1335
   End
   Begin VB.CommandButton Command2 
      Caption         =   "系数计算"
      Height          =   375
      Left            =   360
      TabIndex        =   1
      Top             =   1440
      Width           =   1335
   End
   Begin VB.CommandButton Command1 
      Caption         =   "读入数据"
      Height          =   375
      Left            =   360
      TabIndex        =   0
      Top             =   480
      Width           =   1335
   End
End
Attribute VB_Name = "Form1"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = True
Attribute VB_Exposed = False
Private Sub Command1_Click()
    Call InputSJ
End Sub

Private Sub Command2_Click()
    Call JZSX
End Sub

Private Sub Command3_Click()
    Call OutSJ
End Sub

Private Sub Command4_Click()
    Dim i As Integer
    
    '求解
    If LEGauss(15, SX, y) = True Then
        MsgBox "求解成功!"
        
    Else
        MsgBox "求解失败"
    End If
End Sub

Private Sub Command5_Click()
    If NHDC(20, Xi(), Yi(), Zi()) > c * 100 Then
        MsgBox "拟合度为:" & NHDC(20, Xi(), Yi(), Zi()) & "%," & " 满足要求"
    Else
        MsgBox "拟合度不满足要求"
    End If
End Sub

Private Sub Command6_Click()
    Dim QSXZ As Double
    QSXZ = XZX(20, 15, Sregress, Sresidual)
End Sub

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