📄 obstacks.texi
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@node Obstacks,Licenses,Functions,Top@chapter Obstacks@cindex obstacksAn @dfn{obstack} is a pool of memory containing a stack of objects. Youcan create any number of separate obstacks, and then allocate objects inspecified obstacks. Within each obstack, the last object allocated mustalways be the first one freed, but distinct obstacks are independent ofeach other.Aside from this one constraint of order of freeing, obstacks are totallygeneral: an obstack can contain any number of objects of any size. Theyare implemented with macros, so allocation is usually very fast as long asthe objects are usually small. And the only space overhead per object isthe padding needed to start each object on a suitable boundary.@menu* Creating Obstacks:: How to declare an obstack in your program.* Preparing for Obstacks:: Preparations needed before you can use obstacks.* Allocation in an Obstack:: Allocating objects in an obstack.* Freeing Obstack Objects:: Freeing objects in an obstack.* Obstack Functions:: The obstack functions are both functions and macros.* Growing Objects:: Making an object bigger by stages.* Extra Fast Growing:: Extra-high-efficiency (though more complicated) growing objects.* Status of an Obstack:: Inquiries about the status of an obstack.* Obstacks Data Alignment:: Controlling alignment of objects in obstacks.* Obstack Chunks:: How obstacks obtain and release chunks; efficiency considerations.* Summary of Obstacks::@end menu@node Creating Obstacks@section Creating ObstacksThe utilities for manipulating obstacks are declared in the headerfile @file{obstack.h}.@pindex obstack.h@comment obstack.h@comment GNU@deftp {Data Type} {struct obstack}An obstack is represented by a data structure of type @code{structobstack}. This structure has a small fixed size; it records the statusof the obstack and how to find the space in which objects are allocated.It does not contain any of the objects themselves. You should not tryto access the contents of the structure directly; use only the functionsdescribed in this chapter.@end deftpYou can declare variables of type @code{struct obstack} and use them asobstacks, or you can allocate obstacks dynamically like any other kindof object. Dynamic allocation of obstacks allows your program to have avariable number of different stacks. (You can even allocate anobstack structure in another obstack, but this is rarely useful.)All the functions that work with obstacks require you to specify whichobstack to use. You do this with a pointer of type @code{struct obstack*}. In the following, we often say ``an obstack'' when strictlyspeaking the object at hand is such a pointer.The objects in the obstack are packed into large blocks called@dfn{chunks}. The @code{struct obstack} structure points to a chain ofthe chunks currently in use.The obstack library obtains a new chunk whenever you allocate an objectthat won't fit in the previous chunk. Since the obstack library manageschunks automatically, you don't need to pay much attention to them, butyou do need to supply a function which the obstack library should use toget a chunk. Usually you supply a function which uses @code{malloc}directly or indirectly. You must also supply a function to free a chunk.These matters are described in the following section.@node Preparing for Obstacks@section Preparing for Using ObstacksEach source file in which you plan to use the obstack functionsmust include the header file @file{obstack.h}, like this:@smallexample#include <obstack.h>@end smallexample@findex obstack_chunk_alloc@findex obstack_chunk_freeAlso, if the source file uses the macro @code{obstack_init}, it mustdeclare or define two functions or macros that will be called by theobstack library. One, @code{obstack_chunk_alloc}, is used to allocatethe chunks of memory into which objects are packed. The other,@code{obstack_chunk_free}, is used to return chunks when the objects inthem are freed. These macros should appear before any use of obstacksin the source file.Usually these are defined to use @code{malloc} via the intermediary@code{xmalloc} (@pxref{Unconstrained Allocation, , , libc, The GNU C Library Reference Manual}). This is done withthe following pair of macro definitions:@smallexample#define obstack_chunk_alloc xmalloc#define obstack_chunk_free free@end smallexample@noindentThough the memory you get using obstacks really comes from @code{malloc},using obstacks is faster because @code{malloc} is called less often, forlarger blocks of memory. @xref{Obstack Chunks}, for full details.At run time, before the program can use a @code{struct obstack} objectas an obstack, it must initialize the obstack by calling@code{obstack_init}.@comment obstack.h@comment GNU@deftypefun int obstack_init (struct obstack *@var{obstack-ptr})Initialize obstack @var{obstack-ptr} for allocation of objects. Thisfunction calls the obstack's @code{obstack_chunk_alloc} function. Ifallocation of memory fails, the function pointed to by@code{obstack_alloc_failed_handler} is called. The @code{obstack_init}function always returns 1 (Compatibility notice: Former versions ofobstack returned 0 if allocation failed).@end deftypefunHere are two examples of how to allocate the space for an obstack andinitialize it. First, an obstack that is a static variable:@smallexamplestatic struct obstack myobstack;@dots{}obstack_init (&myobstack);@end smallexample@noindentSecond, an obstack that is itself dynamically allocated:@smallexamplestruct obstack *myobstack_ptr = (struct obstack *) xmalloc (sizeof (struct obstack));obstack_init (myobstack_ptr);@end smallexample@comment obstack.h@comment GNU@defvar obstack_alloc_failed_handlerThe value of this variable is a pointer to a function that@code{obstack} uses when @code{obstack_chunk_alloc} fails to allocatememory. The default action is to print a message and abort.You should supply a function that either calls @code{exit}(@pxref{Program Termination, , , libc, The GNU C Library Reference Manual}) or @code{longjmp} (@pxref{Non-LocalExits, , , libc, The GNU C Library Reference Manual}) and doesn't return.@smallexamplevoid my_obstack_alloc_failed (void)@dots{}obstack_alloc_failed_handler = &my_obstack_alloc_failed;@end smallexample@end defvar@node Allocation in an Obstack@section Allocation in an Obstack@cindex allocation (obstacks)The most direct way to allocate an object in an obstack is with@code{obstack_alloc}, which is invoked almost like @code{malloc}.@comment obstack.h@comment GNU@deftypefun {void *} obstack_alloc (struct obstack *@var{obstack-ptr}, int @var{size})This allocates an uninitialized block of @var{size} bytes in an obstackand returns its address. Here @var{obstack-ptr} specifies which obstackto allocate the block in; it is the address of the @code{struct obstack}object which represents the obstack. Each obstack function or macrorequires you to specify an @var{obstack-ptr} as the first argument.This function calls the obstack's @code{obstack_chunk_alloc} function ifit needs to allocate a new chunk of memory; it calls@code{obstack_alloc_failed_handler} if allocation of memory by@code{obstack_chunk_alloc} failed.@end deftypefunFor example, here is a function that allocates a copy of a string @var{str}in a specific obstack, which is in the variable @code{string_obstack}:@smallexamplestruct obstack string_obstack;char *copystring (char *string)@{ size_t len = strlen (string) + 1; char *s = (char *) obstack_alloc (&string_obstack, len); memcpy (s, string, len); return s;@}@end smallexampleTo allocate a block with specified contents, use the function@code{obstack_copy}, declared like this:@comment obstack.h@comment GNU@deftypefun {void *} obstack_copy (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})This allocates a block and initializes it by copying @var{size}bytes of data starting at @var{address}. It calls@code{obstack_alloc_failed_handler} if allocation of memory by@code{obstack_chunk_alloc} failed.@end deftypefun@comment obstack.h@comment GNU@deftypefun {void *} obstack_copy0 (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})Like @code{obstack_copy}, but appends an extra byte containing a nullcharacter. This extra byte is not counted in the argument @var{size}.@end deftypefunThe @code{obstack_copy0} function is convenient for copying a sequenceof characters into an obstack as a null-terminated string. Here is anexample of its use:@smallexamplechar *obstack_savestring (char *addr, int size)@{ return obstack_copy0 (&myobstack, addr, size);@}@end smallexample@noindentContrast this with the previous example of @code{savestring} using@code{malloc} (@pxref{Basic Allocation, , , libc, The GNU C Library Reference Manual}).@node Freeing Obstack Objects@section Freeing Objects in an Obstack@cindex freeing (obstacks)To free an object allocated in an obstack, use the function@code{obstack_free}. Since the obstack is a stack of objects, freeingone object automatically frees all other objects allocated more recentlyin the same obstack.@comment obstack.h@comment GNU@deftypefun void obstack_free (struct obstack *@var{obstack-ptr}, void *@var{object})If @var{object} is a null pointer, everything allocated in the obstackis freed. Otherwise, @var{object} must be the address of an objectallocated in the obstack. Then @var{object} is freed, along witheverything allocated in @var{obstack} since @var{object}.@end deftypefunNote that if @var{object} is a null pointer, the result is anuninitialized obstack. To free all memory in an obstack but leave itvalid for further allocation, call @code{obstack_free} with the addressof the first object allocated on the obstack:@smallexampleobstack_free (obstack_ptr, first_object_allocated_ptr);@end smallexampleRecall that the objects in an obstack are grouped into chunks. When allthe objects in a chunk become free, the obstack library automaticallyfrees the chunk (@pxref{Preparing for Obstacks}). Then otherobstacks, or non-obstack allocation, can reuse the space of the chunk.@node Obstack Functions@section Obstack Functions and Macros@cindex macrosThe interfaces for using obstacks may be defined either as functions oras macros, depending on the compiler. The obstack facility works withall C compilers, including both @w{ISO C} and traditional C, but there areprecautions you must take if you plan to use compilers other than GNU C.If you are using an old-fashioned @w{non-ISO C} compiler, all the obstack``functions'' are actually defined only as macros. You can call thesemacros like functions, but you cannot use them in any other way (forexample, you cannot take their address).Calling the macros requires a special precaution: namely, the firstoperand (the obstack pointer) may not contain any side effects, becauseit may be computed more than once. For example, if you write this:@smallexampleobstack_alloc (get_obstack (), 4);@end smallexample@noindentyou will find that @code{get_obstack} may be called several times.If you use @code{*obstack_list_ptr++} as the obstack pointer argument,you will get very strange results since the incrementation may occurseveral times.In @w{ISO C}, each function has both a macro definition and a functiondefinition. The function definition is used if you take the address of thefunction without calling it. An ordinary call uses the macro definition bydefault, but you can request the function definition instead by writing thefunction name in parentheses, as shown here:@smallexamplechar *x;void *(*funcp) ();/* @r{Use the macro}. */x = (char *) obstack_alloc (obptr, size);/* @r{Call the function}. */x = (char *) (obstack_alloc) (obptr, size);/* @r{Take the address of the function}. */funcp = obstack_alloc;@end smallexample@noindentThis is the same situation that exists in @w{ISO C} for the standard libraryfunctions. @xref{Macro Definitions, , , libc, The GNU C Library Reference Manual}.@strong{Warning:} When you do use the macros, you must observe theprecaution of avoiding side effects in the first operand, even in @w{ISO C}.If you use the GNU C compiler, this precaution is not necessary, becausevarious language extensions in GNU C permit defining the macros so as tocompute each argument only once.@node Growing Objects@section Growing Objects@cindex growing objects (in obstacks)@cindex changing the size of a block (obstacks)Because memory in obstack chunks is used sequentially, it is possible tobuild up an object step by step, adding one or more bytes at a time to theend of the object. With this technique, you do not need to know how muchdata you will put in the object until you come to the end of it. We callthis the technique of @dfn{growing objects}. The special functionsfor adding data to the growing object are described in this section.You don't need to do anything special when you start to grow an object.Using one of the functions to add data to the object automaticallystarts it. However, it is necessary to say explicitly when the object isfinished. This is done with the function @code{obstack_finish}.The actual address of the object thus built up is not known until theobject is finished. Until then, it always remains possible that you willadd so much data that the object must be copied into a new chunk.While the obstack is in use for a growing object, you cannot use it forordinary allocation of another object. If you try to do so, the spacealready added to the growing object will become part of the other object.@comment obstack.h@comment GNU@deftypefun void obstack_blank (struct obstack *@var{obstack-ptr}, int @var{size})The most basic function for adding to a growing object is@code{obstack_blank}, which adds space without initializing it.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_grow (struct obstack *@var{obstack-ptr}, void *@var{data}, int @var{size})To add a block of initialized space, use @code{obstack_grow}, which isthe growing-object analogue of @code{obstack_copy}. It adds @var{size}bytes of data to the growing object, copying the contents from@var{data}.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_grow0 (struct obstack *@var{obstack-ptr}, void *@var{data}, int @var{size})This is the growing-object analogue of @code{obstack_copy0}. It adds@var{size} bytes copied from @var{data}, followed by an additional nullcharacter.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_1grow (struct obstack *@var{obstack-ptr}, char @var{c})To add one character at a time, use the function @code{obstack_1grow}.It adds a single byte containing @var{c} to the growing object.@end deftypefun@comment obstack.h@comment GNU
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