📄 secant.m
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function [x,k] = secant (x0,x1,tol,m,f,dm)
%----------------------------------------------------------------
% Usage: [x,k] = secant (x0,x1,tol,m,f,dm)
%
% Description: Apply the secant method to find a root of:
%
% f(x) = 0
%
% Inputs: x0 = first initial guess
% x1 = second initial guess (x1 <> x0)
% tol = error tolerance used to terminate search
% (tol >= 0)
% m = maximum number of iterations (m >= 1)
% f = string containing name of user-supplied
% function. The function f is of the form:
%
% function y = f(x)
%
% dm = optional display mode. If present,
% intermediate results are displayed.
%
% Outputs: x = Estimated root of f(x) = 0
% k = number of iterations peroformed. If k < m,
% then the following convergence criterion
% was satisfied:
%
% |f(x)| < eps
%----------------------------------------------------------------
% Initialize
if abs(x1-x0) < eps
fprintf ('Secant requires that x1 <> x0.\n');
return
end
tol = args (tol,0,tol,3,'secant');
m = args (m,1,m,4,'secant');
display = nargin > 5;
f0 = feval(f,x0);
f1 = feval(f,x1);
if display
fprintf ('\n 0 & %10.7f & %10.7f \\\\',x0,abs(f0));
fprintf ('\n 1 & %10.7f & %10.7f \\\\',x1,abs(f1));
fprintf ('\n \\hline');
end
% Find root
k = 1;
y = eps + 1;
while (y > eps) & (k <= m);
x2 = x1 - (x1-x0)*f1/(f1-f0);
x0 = x1;
f0 = f1;
x1 = x2;
f1 = feval(f,x2);
y = abs(f1);
if display
fprintf ('\n%2g & %10.7f & %10.7f \\\\',k+1,x1,y);
end
k = k + 1;
end
% Finalize
x = x2;
k = k - 1;
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