📄 e263.m
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%-----------------------------------------------------------------------
% Example 2.6.3 Successive Under-Relaxation Iterative Method
%-----------------------------------------------------------------------
clc
clear
fprintf ('Example 2.6.3: Successive Under-Relaxation Method\n')
A = [5 0 -2 ; 3 5 1 ; 0 -3 4];
b = [7 ; 2 ; -4];
n = 3;
show ('A',A)
show ('b',b)
x = zeros(n,1);
fprintf ('\n');
fprintf ('k 0.7 0.8 0.9 1.0 1.1\n');
fprintf ('-------------------------------------------------------------\n');
for k = 0 : 9
fprintf ('%d ',k);
for j = 1 : 5
alpha = 0.6 + j/10.0;
x = zeros (n,1);
if k > 0
[x,i] = sr (x,A,b,alpha,0,k);
end
fprintf (' %10.7f ',residual(A,b,x));
end
fprintf ('\n');
end
fprintf ('-------------------------------------------------------------\n');
wait
%-----------------------------------------------------------------------
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