📄 e1091.m
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%-----------------------------------------------------------------------
% Example 10.9.1: Heat Exchanger Frequency Response
%-----------------------------------------------------------------------
% Initialize
clc % clear screen
clear % clear variables
n = 256; % number of samples
T = 0.25; % sampling interval (min)
fs = 1/T; % sampling rate (samples/min)
a = 10; % gain (deg C-m^3/min)
tau = 4.5; % time constant (min)
Td = 1.5; % time delay (min)
u = zeros (n,1); % unit pulse input
y = zeros (n,1); % pulse response
t = zeros (n,1); % discrete times
% Compute pulse response of heat exchanger
fprintf ('Example 10.9.1: Heat Exchanger Frequency Response\n');
u(1) = 1;
m = round (Td/T);
for k = 1 : n
t(k) = (k-1)*T;
if k > max(m+1,1)
y(k) = y(k-1) + (T/tau)*(a*u(k-1-m) - y(k-1));
end
end
% Compute and display frequency response
[A,phi,f] = freqrsp (u,y,fs);
graphxy(f(1:n/2),A(1:n/2),'Magnitude Response','f (samples/min)','A')
%-----------------------------------------------------------------------
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