perldsc.1

视频监控网络部分的协议ddns,的模块的实现代码,请大家大胆指正.

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.\" ========================================================================
.\"
.IX Title "PERLDSC 1"
.TH PERLDSC 1 "2007-12-18" "perl v5.10.0" "Perl Programmers Reference Guide"
.\" For nroff, turn off justification.  Always turn off hyphenation; it makes
.\" way too many mistakes in technical documents.
.if n .ad l
.nh
.SH "NAME"
perldsc \- Perl Data Structures Cookbook
.IX Xref "data structure complex data structure struct"
.SH "DESCRIPTION"
.IX Header "DESCRIPTION"
The single feature most sorely lacking in the Perl programming language
prior to its 5.0 release was complex data structures.  Even without direct
language support, some valiant programmers did manage to emulate them, but
it was hard work and not for the faint of heart.  You could occasionally
get away with the \f(CW$m{$AoA,$b}\fR notation borrowed from \fBawk\fR in which the
keys are actually more like a single concatenated string \f(CW"$AoA$b"\fR, but
traversal and sorting were difficult.  More desperate programmers even
hacked Perl's internal symbol table directly, a strategy that proved hard
to develop and maintain\*(--to put it mildly.
.PP
The 5.0 release of Perl let us have complex data structures.  You
may now write something like this and all of a sudden, you'd have an array
with three dimensions!
.PP
.Vb 8
\&    for $x (1 .. 10) {
\&        for $y (1 .. 10) {
\&            for $z (1 .. 10) {
\&                $AoA[$x][$y][$z] =
\&                    $x ** $y + $z;
\&            }
\&        }
\&    }
.Ve
.PP
Alas, however simple this may appear, underneath it's a much more
elaborate construct than meets the eye!
.PP
How do you print it out?  Why can't you say just \f(CW\*(C`print @AoA\*(C'\fR?  How do
you sort it?  How can you pass it to a function or get one of these back
from a function?  Is it an object?  Can you save it to disk to read
back later?  How do you access whole rows or columns of that matrix?  Do
all the values have to be numeric?
.PP
As you see, it's quite easy to become confused.  While some small portion
of the blame for this can be attributed to the reference-based
implementation, it's really more due to a lack of existing documentation with
examples designed for the beginner.
.PP
This document is meant to be a detailed but understandable treatment of the
many different sorts of data structures you might want to develop.  It
should also serve as a cookbook of examples.  That way, when you need to
create one of these complex data structures, you can just pinch, pilfer, or
purloin a drop-in example from here.
.PP
Let's look at each of these possible constructs in detail.  There are separate
sections on each of the following:
.IP "\(bu" 5
arrays of arrays
.IP "\(bu" 5
hashes of arrays
.IP "\(bu" 5
arrays of hashes
.IP "\(bu" 5
hashes of hashes
.IP "\(bu" 5
more elaborate constructs
.PP
But for now, let's look at general issues common to all
these types of data structures.
.SH "REFERENCES"
.IX Xref "reference dereference dereferencing pointer"
.IX Header "REFERENCES"
The most important thing to understand about all data structures in Perl
\&\*(-- including multidimensional arrays\*(--is that even though they might
appear otherwise, Perl \f(CW@ARRAY\fRs and \f(CW%HASH\fRes are all internally
one-dimensional.  They can hold only scalar values (meaning a string,
number, or a reference).  They cannot directly contain other arrays or
hashes, but instead contain \fIreferences\fR to other arrays or hashes.
.IX Xref "multidimensional array array, multidimensional"
.PP
You can't use a reference to an array or hash in quite the same way that you
would a real array or hash.  For C or \*(C+ programmers unused to
distinguishing between arrays and pointers to the same, this can be
confusing.  If so, just think of it as the difference between a structure
and a pointer to a structure.
.PP
You can (and should) read more about references in the \fIperlref\fR\|(1) man
page.  Briefly, references are rather like pointers that know what they
point to.  (Objects are also a kind of reference, but we won't be needing
them right away\*(--if ever.)  This means that when you have something which
looks to you like an access to a two-or-more-dimensional array and/or hash,
what's really going on is that the base type is
merely a one-dimensional entity that contains references to the next
level.  It's just that you can \fIuse\fR it as though it were a
two-dimensional one.  This is actually the way almost all C
multidimensional arrays work as well.
.PP
.Vb 4
\&    $array[7][12]                       # array of arrays
\&    $array[7]{string}                   # array of hashes
\&    $hash{string}[7]                    # hash of arrays
\&    $hash{string}{\*(Aqanother string\*(Aq}     # hash of hashes
.Ve
.PP
Now, because the top level contains only references, if you try to print
out your array in with a simple \fIprint()\fR function, you'll get something
that doesn't look very nice, like this:
.PP
.Vb 5
\&    @AoA = ( [2, 3], [4, 5, 7], [0] );
\&    print $AoA[1][2];
\&  7
\&    print @AoA;
\&  ARRAY(0x83c38)ARRAY(0x8b194)ARRAY(0x8b1d0)
.Ve
.PP
That's because Perl doesn't (ever) implicitly dereference your variables.
If you want to get at the thing a reference is referring to, then you have
to do this yourself using either prefix typing indicators, like
\&\f(CW\*(C`${$blah}\*(C'\fR, \f(CW\*(C`@{$blah}\*(C'\fR, \f(CW\*(C`@{$blah[$i]}\*(C'\fR, or else postfix pointer arrows,
like \f(CW\*(C`$a\->[3]\*(C'\fR, \f(CW\*(C`$h\->{fred}\*(C'\fR, or even \f(CW\*(C`$ob\->method()\->[3]\*(C'\fR.
.SH "COMMON MISTAKES"
.IX Header "COMMON MISTAKES"
The two most common mistakes made in constructing something like
an array of arrays is either accidentally counting the number of
elements or else taking a reference to the same memory location
repeatedly.  Here's the case where you just get the count instead
of a nested array:
.PP
.Vb 4
\&    for $i (1..10) {
\&        @array = somefunc($i);
\&        $AoA[$i] = @array;      # WRONG!
\&    }
.Ve
.PP
That's just the simple case of assigning an array to a scalar and getting
its element count.  If that's what you really and truly want, then you
might do well to consider being a tad more explicit about it, like this:
.PP
.Vb 4
\&    for $i (1..10) {
\&        @array = somefunc($i);
\&        $counts[$i] = scalar @array;
\&    }
.Ve
.PP
Here's the case of taking a reference to the same memory location
again and again:
.PP
.Vb 4
\&    for $i (1..10) {
\&        @array = somefunc($i);
\&        $AoA[$i] = \e@array;     # WRONG!
\&    }
.Ve
.PP
So, what's the big problem with that?  It looks right, doesn't it?
After all, I just told you that you need an array of references, so by
golly, you've made me one!
.PP
Unfortunately, while this is true, it's still broken.  All the references
in \f(CW@AoA\fR refer to the \fIvery same place\fR, and they will therefore all hold
whatever was last in \f(CW@array\fR!  It's similar to the problem demonstrated in
the following C program:
.PP
.Vb 5
\&    #include <pwd.h>
\&    main() {
\&        struct passwd *getpwnam(), *rp, *dp;
\&        rp = getpwnam("root");
\&        dp = getpwnam("daemon");
\&
\&        printf("daemon name is %s\enroot name is %s\en",
\&                dp\->pw_name, rp\->pw_name);
\&    }
.Ve
.PP
Which will print
.PP
.Vb 2
\&    daemon name is daemon
\&    root name is daemon
.Ve
.PP
The problem is that both \f(CW\*(C`rp\*(C'\fR and \f(CW\*(C`dp\*(C'\fR are pointers to the same location
in memory!  In C, you'd have to remember to \fImalloc()\fR yourself some new
memory.  In Perl, you'll want to use the array constructor \f(CW\*(C`[]\*(C'\fR or the
hash constructor \f(CW\*(C`{}\*(C'\fR instead.   Here's the right way to do the preceding
broken code fragments:
.IX Xref "[] {}"
.PP
.Vb 4
\&    for $i (1..10) {
\&        @array = somefunc($i);
\&        $AoA[$i] = [ @array ];
\&    }
.Ve
.PP
The square brackets make a reference to a new array with a \fIcopy\fR
of what's in \f(CW@array\fR at the time of the assignment.  This is what
you want.
.PP
Note that this will produce something similar, but it's
much harder to read: