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📄 bigunsigned.cc

📁 用C++ 包装了大整数这个类
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#include "BigUnsigned.hh"// Memory management definitions have moved to the bottom of NumberlikeArray.hh.// The templates used by these constructors and converters are at the bottom of// BigUnsigned.hh.BigUnsigned::BigUnsigned(unsigned long  x) { initFromPrimitive      (x); }BigUnsigned::BigUnsigned(unsigned int   x) { initFromPrimitive      (x); }BigUnsigned::BigUnsigned(unsigned short x) { initFromPrimitive      (x); }BigUnsigned::BigUnsigned(         long  x) { initFromSignedPrimitive(x); }BigUnsigned::BigUnsigned(         int   x) { initFromSignedPrimitive(x); }BigUnsigned::BigUnsigned(         short x) { initFromSignedPrimitive(x); }unsigned long  BigUnsigned::toUnsignedLong () const { return convertToPrimitive      <unsigned long >(); }unsigned int   BigUnsigned::toUnsignedInt  () const { return convertToPrimitive      <unsigned int  >(); }unsigned short BigUnsigned::toUnsignedShort() const { return convertToPrimitive      <unsigned short>(); }long           BigUnsigned::toLong         () const { return convertToSignedPrimitive<         long >(); }int            BigUnsigned::toInt          () const { return convertToSignedPrimitive<         int  >(); }short          BigUnsigned::toShort        () const { return convertToSignedPrimitive<         short>(); }// BIT/BLOCK ACCESSORSvoid BigUnsigned::setBlock(Index i, Blk newBlock) {	if (newBlock == 0) {		if (i < len) {			blk[i] = 0;			zapLeadingZeros();		}		// If i >= len, no effect.	} else {		if (i >= len) {			// The nonzero block extends the number.			allocateAndCopy(i+1);			// Zero any added blocks that we aren't setting.			for (Index j = len; j < i; j++)				blk[j] = 0;			len = i+1;		}		blk[i] = newBlock;	}}/* Evidently the compiler wants BigUnsigned:: on the return type because, at * that point, it hasn't yet parsed the BigUnsigned:: on the name to get the * proper scope. */BigUnsigned::Index BigUnsigned::bitLength() const {	if (isZero())		return 0;	else {		Blk leftmostBlock = getBlock(len - 1);		Index leftmostBlockLen = 0;		while (leftmostBlock != 0) {			leftmostBlock >>= 1;			leftmostBlockLen++;		}		return leftmostBlockLen + (len - 1) * N;	}}void BigUnsigned::setBit(Index bi, bool newBit) {	Index blockI = bi / N;	Blk block = getBlock(blockI), mask = 1 << (bi % N);	block = newBit ? (block | mask) : (block & ~mask);	setBlock(blockI, block);}// COMPARISONBigUnsigned::CmpRes BigUnsigned::compareTo(const BigUnsigned &x) const {	// A bigger length implies a bigger number.	if (len < x.len)		return less;	else if (len > x.len)		return greater;	else {		// Compare blocks one by one from left to right.		Index i = len;		while (i > 0) {			i--;			if (blk[i] == x.blk[i])				continue;			else if (blk[i] > x.blk[i])				return greater;			else				return less;		}		// If no blocks differed, the numbers are equal.		return equal;	}}// COPY-LESS OPERATIONS/* * On most calls to copy-less operations, it's safe to read the inputs little by * little and write the outputs little by little.  However, if one of the * inputs is coming from the same variable into which the output is to be * stored (an "aliased" call), we risk overwriting the input before we read it. * In this case, we first compute the result into a temporary BigUnsigned * variable and then copy it into the requested output variable *this. * Each put-here operation uses the DTRT_ALIASED macro (Do The Right Thing on * aliased calls) to generate code for this check. *  * I adopted this approach on 2007.02.13 (see Assignment Operators in * BigUnsigned.hh).  Before then, put-here operations rejected aliased calls * with an exception.  I think doing the right thing is better. *  * Some of the put-here operations can probably handle aliased calls safely * without the extra copy because (for example) they process blocks strictly * right-to-left.  At some point I might determine which ones don't need the * copy, but my reasoning would need to be verified very carefully.  For now * I'll leave in the copy. */#define DTRT_ALIASED(cond, op) \	if (cond) { \		BigUnsigned tmpThis; \		tmpThis.op; \		*this = tmpThis; \		return; \	}void BigUnsigned::add(const BigUnsigned &a, const BigUnsigned &b) {	DTRT_ALIASED(this == &a || this == &b, add(a, b));	// If one argument is zero, copy the other.	if (a.len == 0) {		operator =(b);		return;	} else if (b.len == 0) {		operator =(a);		return;	}	// Some variables...	// Carries in and out of an addition stage	bool carryIn, carryOut;	Blk temp;	Index i;	// a2 points to the longer input, b2 points to the shorter	const BigUnsigned *a2, *b2;	if (a.len >= b.len) {		a2 = &a;		b2 = &b;	} else {		a2 = &b;		b2 = &a;	}	// Set prelimiary length and make room in this BigUnsigned	len = a2->len + 1;	allocate(len);	// For each block index that is present in both inputs...	for (i = 0, carryIn = false; i < b2->len; i++) {		// Add input blocks		temp = a2->blk[i] + b2->blk[i];		// If a rollover occurred, the result is less than either input.		// This test is used many times in the BigUnsigned code.		carryOut = (temp < a2->blk[i]);		// If a carry was input, handle it		if (carryIn) {			temp++;			carryOut |= (temp == 0);		}		blk[i] = temp; // Save the addition result		carryIn = carryOut; // Pass the carry along	}	// If there is a carry left over, increase blocks until	// one does not roll over.	for (; i < a2->len && carryIn; i++) {		temp = a2->blk[i] + 1;		carryIn = (temp == 0);		blk[i] = temp;	}	// If the carry was resolved but the larger number	// still has blocks, copy them over.	for (; i < a2->len; i++)		blk[i] = a2->blk[i];	// Set the extra block if there's still a carry, decrease length otherwise	if (carryIn)		blk[i] = 1;	else		len--;}void BigUnsigned::subtract(const BigUnsigned &a, const BigUnsigned &b) {	DTRT_ALIASED(this == &a || this == &b, subtract(a, b));	if (b.len == 0) {		// If b is zero, copy a.		operator =(a);		return;	} else if (a.len < b.len)		// If a is shorter than b, the result is negative.		throw "BigUnsigned::subtract: "			"Negative result in unsigned calculation";	// Some variables...	bool borrowIn, borrowOut;	Blk temp;	Index i;	// Set preliminary length and make room	len = a.len;	allocate(len);	// For each block index that is present in both inputs...	for (i = 0, borrowIn = false; i < b.len; i++) {		temp = a.blk[i] - b.blk[i];		// If a reverse rollover occurred,		// the result is greater than the block from a.		borrowOut = (temp > a.blk[i]);		// Handle an incoming borrow		if (borrowIn) {			borrowOut |= (temp == 0);			temp--;		}		blk[i] = temp; // Save the subtraction result		borrowIn = borrowOut; // Pass the borrow along	}	// If there is a borrow left over, decrease blocks until	// one does not reverse rollover.	for (; i < a.len && borrowIn; i++) {		borrowIn = (a.blk[i] == 0);		blk[i] = a.blk[i] - 1;	}	/* If there's still a borrow, the result is negative.	 * Throw an exception, but zero out this object so as to leave it in a	 * predictable state. */	if (borrowIn) {		len = 0;		throw "BigUnsigned::subtract: Negative result in unsigned calculation";	} else		// Copy over the rest of the blocks		for (; i < a.len; i++)			blk[i] = a.blk[i];	// Zap leading zeros	zapLeadingZeros();}/* * About the multiplication and division algorithms: * * I searched unsucessfully for fast C++ built-in operations like the `b_0' * and `c_0' Knuth describes in Section 4.3.1 of ``The Art of Computer * Programming'' (replace `place' by `Blk'): * *    ``b_0[:] multiplication of a one-place integer by another one-place *      integer, giving a two-place answer; * *    ``c_0[:] division of a two-place integer by a one-place integer, *      provided that the quotient is a one-place integer, and yielding *      also a one-place remainder.'' * * I also missed his note that ``[b]y adjusting the word size, if * necessary, nearly all computers will have these three operations * available'', so I gave up on trying to use algorithms similar to his. * A future version of the library might include such algorithms; I * would welcome contributions from others for this. * * I eventually decided to use bit-shifting algorithms.  To multiply `a' * and `b', we zero out the result.  Then, for each `1' bit in `a', we * shift `b' left the appropriate amount and add it to the result. * Similarly, to divide `a' by `b', we shift `b' left varying amounts, * repeatedly trying to subtract it from `a'.  When we succeed, we note * the fact by setting a bit in the quotient.  While these algorithms * have the same O(n^2) time complexity as Knuth's, the ``constant factor'' * is likely to be larger. * * Because I used these algorithms, which require single-block addition * and subtraction rather than single-block multiplication and division, * the innermost loops of all four routines are very similar.  Study one * of them and all will become clear. *//* * This is a little inline function used by both the multiplication * routine and the division routine. * * `getShiftedBlock' returns the `x'th block of `num << y'. * `y' may be anything from 0 to N - 1, and `x' may be anything from * 0 to `num.len'. * * Two things contribute to this block: * * (1) The `N - y' low bits of `num.blk[x]', shifted `y' bits left. * * (2) The `y' high bits of `num.blk[x-1]', shifted `N - y' bits right. * * But we must be careful if `x == 0' or `x == num.len', in * which case we should use 0 instead of (2) or (1), respectively. * * If `y == 0', then (2) contributes 0, as it should.  However, * in some computer environments, for a reason I cannot understand, * `a >> b' means `a >> (b % N)'.  This means `num.blk[x-1] >> (N - y)' * will return `num.blk[x-1]' instead of the desired 0 when `y == 0'; * the test `y == 0' handles this case specially. */inline BigUnsigned::Blk getShiftedBlock(const BigUnsigned &num,	BigUnsigned::Index x, unsigned int y) {	BigUnsigned::Blk part1 = (x == 0 || y == 0) ? 0 : (num.blk[x - 1] >> (BigUnsigned::N - y));	BigUnsigned::Blk part2 = (x == num.len) ? 0 : (num.blk[x] << y);	return part1 | part2;}void BigUnsigned::multiply(const BigUnsigned &a, const BigUnsigned &b) {	DTRT_ALIASED(this == &a || this == &b, multiply(a, b));	// If either a or b is zero, set to zero.	if (a.len == 0 || b.len == 0) {		len = 0;		return;	}	/*	 * Overall method:	 *	 * Set this = 0.	 * For each 1-bit of `a' (say the `i2'th bit of block `i'):	 *    Add `b << (i blocks and i2 bits)' to *this.	 */	// Variables for the calculation	Index i, j, k;	unsigned int i2;	Blk temp;	bool carryIn, carryOut;	// Set preliminary length and make room	len = a.len + b.len;	allocate(len);	// Zero out this object	for (i = 0; i < len; i++)		blk[i] = 0;	// For each block of the first number...	for (i = 0; i < a.len; i++) {		// For each 1-bit of that block...		for (i2 = 0; i2 < N; i2++) {			if ((a.blk[i] & (Blk(1) << i2)) == 0)				continue;			/*			 * Add b to this, shifted left i blocks and i2 bits.			 * j is the index in b, and k = i + j is the index in this.			 *			 * `getShiftedBlock', a short inline function defined above,			 * is now used for the bit handling.  It replaces the more			 * complex `bHigh' code, in which each run of the loop dealt			 * immediately with the low bits and saved the high bits to			 * be picked up next time.  The last run of the loop used to			 * leave leftover high bits, which were handled separately.			 * Instead, this loop runs an additional time with j == b.len.			 * These changes were made on 2005.01.11.			 */			for (j = 0, k = i, carryIn = false; j <= b.len; j++, k++) {				/*				 * The body of this loop is very similar to the body of the first loop				 * in `add', except that this loop does a `+=' instead of a `+'.				 */				temp = blk[k] + getShiftedBlock(b, j, i2);

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