📄 bigunsigned.cc
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#include "BigUnsigned.hh"// Memory management definitions have moved to the bottom of NumberlikeArray.hh.// The templates used by these constructors and converters are at the bottom of// BigUnsigned.hh.BigUnsigned::BigUnsigned(unsigned long x) { initFromPrimitive (x); }BigUnsigned::BigUnsigned(unsigned int x) { initFromPrimitive (x); }BigUnsigned::BigUnsigned(unsigned short x) { initFromPrimitive (x); }BigUnsigned::BigUnsigned( long x) { initFromSignedPrimitive(x); }BigUnsigned::BigUnsigned( int x) { initFromSignedPrimitive(x); }BigUnsigned::BigUnsigned( short x) { initFromSignedPrimitive(x); }unsigned long BigUnsigned::toUnsignedLong () const { return convertToPrimitive <unsigned long >(); }unsigned int BigUnsigned::toUnsignedInt () const { return convertToPrimitive <unsigned int >(); }unsigned short BigUnsigned::toUnsignedShort() const { return convertToPrimitive <unsigned short>(); }long BigUnsigned::toLong () const { return convertToSignedPrimitive< long >(); }int BigUnsigned::toInt () const { return convertToSignedPrimitive< int >(); }short BigUnsigned::toShort () const { return convertToSignedPrimitive< short>(); }// BIT/BLOCK ACCESSORSvoid BigUnsigned::setBlock(Index i, Blk newBlock) { if (newBlock == 0) { if (i < len) { blk[i] = 0; zapLeadingZeros(); } // If i >= len, no effect. } else { if (i >= len) { // The nonzero block extends the number. allocateAndCopy(i+1); // Zero any added blocks that we aren't setting. for (Index j = len; j < i; j++) blk[j] = 0; len = i+1; } blk[i] = newBlock; }}/* Evidently the compiler wants BigUnsigned:: on the return type because, at * that point, it hasn't yet parsed the BigUnsigned:: on the name to get the * proper scope. */BigUnsigned::Index BigUnsigned::bitLength() const { if (isZero()) return 0; else { Blk leftmostBlock = getBlock(len - 1); Index leftmostBlockLen = 0; while (leftmostBlock != 0) { leftmostBlock >>= 1; leftmostBlockLen++; } return leftmostBlockLen + (len - 1) * N; }}void BigUnsigned::setBit(Index bi, bool newBit) { Index blockI = bi / N; Blk block = getBlock(blockI), mask = 1 << (bi % N); block = newBit ? (block | mask) : (block & ~mask); setBlock(blockI, block);}// COMPARISONBigUnsigned::CmpRes BigUnsigned::compareTo(const BigUnsigned &x) const { // A bigger length implies a bigger number. if (len < x.len) return less; else if (len > x.len) return greater; else { // Compare blocks one by one from left to right. Index i = len; while (i > 0) { i--; if (blk[i] == x.blk[i]) continue; else if (blk[i] > x.blk[i]) return greater; else return less; } // If no blocks differed, the numbers are equal. return equal; }}// COPY-LESS OPERATIONS/* * On most calls to copy-less operations, it's safe to read the inputs little by * little and write the outputs little by little. However, if one of the * inputs is coming from the same variable into which the output is to be * stored (an "aliased" call), we risk overwriting the input before we read it. * In this case, we first compute the result into a temporary BigUnsigned * variable and then copy it into the requested output variable *this. * Each put-here operation uses the DTRT_ALIASED macro (Do The Right Thing on * aliased calls) to generate code for this check. * * I adopted this approach on 2007.02.13 (see Assignment Operators in * BigUnsigned.hh). Before then, put-here operations rejected aliased calls * with an exception. I think doing the right thing is better. * * Some of the put-here operations can probably handle aliased calls safely * without the extra copy because (for example) they process blocks strictly * right-to-left. At some point I might determine which ones don't need the * copy, but my reasoning would need to be verified very carefully. For now * I'll leave in the copy. */#define DTRT_ALIASED(cond, op) \ if (cond) { \ BigUnsigned tmpThis; \ tmpThis.op; \ *this = tmpThis; \ return; \ }void BigUnsigned::add(const BigUnsigned &a, const BigUnsigned &b) { DTRT_ALIASED(this == &a || this == &b, add(a, b)); // If one argument is zero, copy the other. if (a.len == 0) { operator =(b); return; } else if (b.len == 0) { operator =(a); return; } // Some variables... // Carries in and out of an addition stage bool carryIn, carryOut; Blk temp; Index i; // a2 points to the longer input, b2 points to the shorter const BigUnsigned *a2, *b2; if (a.len >= b.len) { a2 = &a; b2 = &b; } else { a2 = &b; b2 = &a; } // Set prelimiary length and make room in this BigUnsigned len = a2->len + 1; allocate(len); // For each block index that is present in both inputs... for (i = 0, carryIn = false; i < b2->len; i++) { // Add input blocks temp = a2->blk[i] + b2->blk[i]; // If a rollover occurred, the result is less than either input. // This test is used many times in the BigUnsigned code. carryOut = (temp < a2->blk[i]); // If a carry was input, handle it if (carryIn) { temp++; carryOut |= (temp == 0); } blk[i] = temp; // Save the addition result carryIn = carryOut; // Pass the carry along } // If there is a carry left over, increase blocks until // one does not roll over. for (; i < a2->len && carryIn; i++) { temp = a2->blk[i] + 1; carryIn = (temp == 0); blk[i] = temp; } // If the carry was resolved but the larger number // still has blocks, copy them over. for (; i < a2->len; i++) blk[i] = a2->blk[i]; // Set the extra block if there's still a carry, decrease length otherwise if (carryIn) blk[i] = 1; else len--;}void BigUnsigned::subtract(const BigUnsigned &a, const BigUnsigned &b) { DTRT_ALIASED(this == &a || this == &b, subtract(a, b)); if (b.len == 0) { // If b is zero, copy a. operator =(a); return; } else if (a.len < b.len) // If a is shorter than b, the result is negative. throw "BigUnsigned::subtract: " "Negative result in unsigned calculation"; // Some variables... bool borrowIn, borrowOut; Blk temp; Index i; // Set preliminary length and make room len = a.len; allocate(len); // For each block index that is present in both inputs... for (i = 0, borrowIn = false; i < b.len; i++) { temp = a.blk[i] - b.blk[i]; // If a reverse rollover occurred, // the result is greater than the block from a. borrowOut = (temp > a.blk[i]); // Handle an incoming borrow if (borrowIn) { borrowOut |= (temp == 0); temp--; } blk[i] = temp; // Save the subtraction result borrowIn = borrowOut; // Pass the borrow along } // If there is a borrow left over, decrease blocks until // one does not reverse rollover. for (; i < a.len && borrowIn; i++) { borrowIn = (a.blk[i] == 0); blk[i] = a.blk[i] - 1; } /* If there's still a borrow, the result is negative. * Throw an exception, but zero out this object so as to leave it in a * predictable state. */ if (borrowIn) { len = 0; throw "BigUnsigned::subtract: Negative result in unsigned calculation"; } else // Copy over the rest of the blocks for (; i < a.len; i++) blk[i] = a.blk[i]; // Zap leading zeros zapLeadingZeros();}/* * About the multiplication and division algorithms: * * I searched unsucessfully for fast C++ built-in operations like the `b_0' * and `c_0' Knuth describes in Section 4.3.1 of ``The Art of Computer * Programming'' (replace `place' by `Blk'): * * ``b_0[:] multiplication of a one-place integer by another one-place * integer, giving a two-place answer; * * ``c_0[:] division of a two-place integer by a one-place integer, * provided that the quotient is a one-place integer, and yielding * also a one-place remainder.'' * * I also missed his note that ``[b]y adjusting the word size, if * necessary, nearly all computers will have these three operations * available'', so I gave up on trying to use algorithms similar to his. * A future version of the library might include such algorithms; I * would welcome contributions from others for this. * * I eventually decided to use bit-shifting algorithms. To multiply `a' * and `b', we zero out the result. Then, for each `1' bit in `a', we * shift `b' left the appropriate amount and add it to the result. * Similarly, to divide `a' by `b', we shift `b' left varying amounts, * repeatedly trying to subtract it from `a'. When we succeed, we note * the fact by setting a bit in the quotient. While these algorithms * have the same O(n^2) time complexity as Knuth's, the ``constant factor'' * is likely to be larger. * * Because I used these algorithms, which require single-block addition * and subtraction rather than single-block multiplication and division, * the innermost loops of all four routines are very similar. Study one * of them and all will become clear. *//* * This is a little inline function used by both the multiplication * routine and the division routine. * * `getShiftedBlock' returns the `x'th block of `num << y'. * `y' may be anything from 0 to N - 1, and `x' may be anything from * 0 to `num.len'. * * Two things contribute to this block: * * (1) The `N - y' low bits of `num.blk[x]', shifted `y' bits left. * * (2) The `y' high bits of `num.blk[x-1]', shifted `N - y' bits right. * * But we must be careful if `x == 0' or `x == num.len', in * which case we should use 0 instead of (2) or (1), respectively. * * If `y == 0', then (2) contributes 0, as it should. However, * in some computer environments, for a reason I cannot understand, * `a >> b' means `a >> (b % N)'. This means `num.blk[x-1] >> (N - y)' * will return `num.blk[x-1]' instead of the desired 0 when `y == 0'; * the test `y == 0' handles this case specially. */inline BigUnsigned::Blk getShiftedBlock(const BigUnsigned &num, BigUnsigned::Index x, unsigned int y) { BigUnsigned::Blk part1 = (x == 0 || y == 0) ? 0 : (num.blk[x - 1] >> (BigUnsigned::N - y)); BigUnsigned::Blk part2 = (x == num.len) ? 0 : (num.blk[x] << y); return part1 | part2;}void BigUnsigned::multiply(const BigUnsigned &a, const BigUnsigned &b) { DTRT_ALIASED(this == &a || this == &b, multiply(a, b)); // If either a or b is zero, set to zero. if (a.len == 0 || b.len == 0) { len = 0; return; } /* * Overall method: * * Set this = 0. * For each 1-bit of `a' (say the `i2'th bit of block `i'): * Add `b << (i blocks and i2 bits)' to *this. */ // Variables for the calculation Index i, j, k; unsigned int i2; Blk temp; bool carryIn, carryOut; // Set preliminary length and make room len = a.len + b.len; allocate(len); // Zero out this object for (i = 0; i < len; i++) blk[i] = 0; // For each block of the first number... for (i = 0; i < a.len; i++) { // For each 1-bit of that block... for (i2 = 0; i2 < N; i2++) { if ((a.blk[i] & (Blk(1) << i2)) == 0) continue; /* * Add b to this, shifted left i blocks and i2 bits. * j is the index in b, and k = i + j is the index in this. * * `getShiftedBlock', a short inline function defined above, * is now used for the bit handling. It replaces the more * complex `bHigh' code, in which each run of the loop dealt * immediately with the low bits and saved the high bits to * be picked up next time. The last run of the loop used to * leave leftover high bits, which were handled separately. * Instead, this loop runs an additional time with j == b.len. * These changes were made on 2005.01.11. */ for (j = 0, k = i, carryIn = false; j <= b.len; j++, k++) { /* * The body of this loop is very similar to the body of the first loop * in `add', except that this loop does a `+=' instead of a `+'. */ temp = blk[k] + getShiftedBlock(b, j, i2);
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