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📄 pictures.java

📁 J2ME编程的50个例子,适合掌上系统的编程
💻 JAVA
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package demo;
import javax.microedition.lcdui.Graphics;
import javax.microedition.lcdui.Image;

public class Pictures {
	private int m_nX;				//图像左上角的X坐标
	private int m_nY;				//图像左上角的Y坐标
	//定义两个个数组,分别不同点的X与Y坐标
	private int m_aDefferX[] = { 73, 70, 54, 57, 30 };
	private int m_aDefferY[] = { 12, 58, 81, 91, 115 };

	//定义数组,标识不同点是否被发现
	private boolean m_bFind[] = 
			{false, false, false, false, false};
	
	private Image m_PictureImg;	//存储两幅相似的图像
	
	public Pictures( int scrWidth, int scrHeight ){
		try{
			m_PictureImg = Image.createImage("/demo/dog.png");
			m_nX = scrWidth/2 - m_PictureImg.getWidth()/2;
			m_nY = scrHeight/2 - m_PictureImg.getHeight()/2;
		}
		catch (Exception ex){}
	}
	
	//获取不同点的个数
	public int getDiffNum(){
		return m_bFind.length;
	}
	
	//返回已找到的不同点的数量
	public int getFindNum(){
		int num = 0;
		for( int n = 0; n < m_bFind.length; n ++ ){
			if( m_bFind[n] == true )
				num ++;
		}
		return num;
	}
	
	//判断某处是否有不同点
	public void CheckDiffer( int x, int y ){
		int lx = m_nX;
		int rx = m_nX + 80;
		for( int n = 0; n < m_bFind.length; n ++ ){
			//判断左边的图像
			if( x >= lx + m_aDefferX[n] - 10 &&
				x <= lx + m_aDefferX[n] + 10 &&
				y >= m_nY + m_aDefferY[n] - 10 &&
				y <= m_nY + m_aDefferY[n] + 10 ){
				m_bFind[n] = true;
				break;
			}
			//判断右边的图像
			if( x >= rx + m_aDefferX[n] - 10 &&
				x <= rx + m_aDefferX[n] + 10 &&
				y >= m_nY + m_aDefferY[n] - 10 &&
				y <= m_nY + m_aDefferY[n] + 10 ){
				m_bFind[n] = true;
				break;
			}
		}
	}
	//显示两幅相似的图像,以及已找到的不同之处
	public void Paint( Graphics g ){
		g.drawImage(m_PictureImg, m_nX, m_nY, 0);
		//在已找出的不同点上画标记
		for( int n = 0; n < m_bFind.length; n ++ ){
			if( m_bFind[n] == true ){
				//在左边图像上画标记
				g.drawArc( m_nX + m_aDefferX[n] - 10,
						m_nY + m_aDefferY[n] - 10, 20, 20, 0, 360 );
				//在右边图像上画标记
				g.drawArc( m_nX + m_aDefferX[n] + 80 - 10,
						m_nY + m_aDefferY[n] - 10, 20, 20, 0, 360  );
			}
		}
	}
}

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