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📁 王元汉
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  uncoupling the equations of motion

 I,T,D(1),D(2)=       1      .12000     -.00734      .04607
 I,T,D(1),D(2)=       2      .24000     -.02361      .17243
 I,T,D(1),D(2)=       3      .36000     -.03385      .34764
 I,T,D(1),D(2)=       4      .48000     -.01994      .53144
 I,T,D(1),D(2)=       5      .60000      .03706      .65613
 I,T,D(1),D(2)=       6      .72000      .14554      .65194
 I,T,D(1),D(2)=       7      .84000      .28215      .54803
 I,T,D(1),D(2)=       8      .96000      .40822      .40382
 I,T,D(1),D(2)=       9     1.08000      .48370      .28449
 I,T,D(1),D(2)=      10     1.20000      .48159      .23611

   by Newmark method  

 I,T,D00(1),D00(2)=   1      .12000     -.00646      .04424
 I,T,D00(1),D00(2)=   2      .24000     -.02077      .16634
 I,T,D00(1),D00(2)=   3      .36000     -.02967      .33790
 I,T,D00(1),D00(2)=   4      .48000     -.01682      .52187
 I,T,D00(1),D00(2)=   5      .60000      .03403      .66210
 I,T,D00(1),D00(2)=   6      .72000      .13090      .69883
 I,T,D00(1),D00(2)=   7      .84000      .26049      .62717
 I,T,D00(1),D00(2)=   8      .96000      .39045      .49460
 I,T,D00(1),D00(2)=   9     1.08000      .48319      .36108
 I,T,D00(1),D00(2)=  10     1.20000      .50857      .27729

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