lessson4_1.lst

陈天祥的《十天学会单片机》的所以C语言源程序

C51 COMPILER V6.12  LESSSON4_1                                                             07/24/2007 09:09:07 PAGE 1   


C51 COMPILER V6.12, COMPILATION OF MODULE LESSSON4_1
OBJECT MODULE PLACED IN .\lessson4_1.OBJ
COMPILER INVOKED BY: C:\Keil\C51\BIN\C51.EXE .\lessson4_1.c DEBUG OBJECTEXTEND

stmt level    source

   1          #include<reg52.h>
   2          #include<intrins.h>
   3          #define uint unsigned int
   4          #define uchar unsigned char
   5          uchar temp,aa,num;
   6          sbit dula=P2^6;
   7          sbit wela=P2^7;
   8          uchar code table[]={
   9          0x3f,0x06,0x5b,0x4f,
  10          0x66,0x6d,0x7d,0x07,
  11          0x7f,0x6f,0x77,0x7c,
  12          0x39,0x5e,0x79,0x71};
  13          void delay(uint z);
  14          void main()
  15          {
  16   1      	num=0;
  17   1      	aa=0;
  18   1      	TMOD=0x01;
  19   1      	TH0=(65536-50000)/256;
  20   1      	TL0=(65536-50000)%256;
  21   1      	EA=1;
  22   1      	ET0=1;
  23   1      	TR0=1;
  24   1      	temp=0xfe;
  25   1      	P1=temp;
  26   1      	dula=1;
  27   1      	P0=table[0];
  28   1      	dula=0;
  29   1      	wela=1;
  30   1      	P0=0xc0;
  31   1      	wela=0;
  32   1      	while(1)
  33   1      	{
  34   2      		delay(1000);
  35   2      		temp=_crol_(temp,1);
  36   2      		P1=temp;
  37   2      	/*	if(aa==40)
  38   2      			{
  39   2      				aa=0;
  40   2      				num++;
  41   2      				if(num==16)
  42   2      					num=0;
  43   2      				dula=1;
  44   2      				P0=table[num];
  45   2      				dula=0;		
  46   2      			}	*/	
  47   2      	}
  48   1      }
  49          
  50          void delay(uint z)
  51          {
  52   1      	uint x,y;
  53   1      	for(x=z;x>0;x--)
  54   1      		for(y=110;y>0;y--);
  55   1      }
C51 COMPILER V6.12  LESSSON4_1                                                             07/24/2007 09:09:07 PAGE 2   

  56          
  57          void timer0() interrupt 1 
  58          {
  59   1      	TH0=(65536-50000)/256;
  60   1      	TL0=(65536-50000)%256;
  61   1      	aa++;
  62   1      		if(aa==40)
  63   1      			{
  64   2      				aa=0;
  65   2      				num++;
  66   2      				if(num==16)
  67   2      					num=0;
  68   2      				dula=1;
  69   2      				P0=table[num];
  70   2      				dula=0;		
  71   2      			}	
  72   1      }


MODULE INFORMATION:   STATIC OVERLAYABLE
   CODE SIZE        =    152    ----
   CONSTANT SIZE    =     16    ----
   XDATA SIZE       =   ----    ----
   PDATA SIZE       =   ----    ----
   DATA SIZE        =      3    ----
   IDATA SIZE       =   ----    ----
   BIT SIZE         =   ----    ----
END OF MODULE INFORMATION.


C51 COMPILATION COMPLETE.  0 WARNING(S),  0 ERROR(S)