📄 迭代法.frm
字号:
VERSION 5.00
Begin VB.Form Form22
BackColor = &H00FFFFFF&
Caption = "迭代法"
ClientHeight = 7365
ClientLeft = 60
ClientTop = 345
ClientWidth = 8685
LinkTopic = "Form17"
ScaleHeight = 7365
ScaleWidth = 8685
StartUpPosition = 3 '窗口缺省
Begin VB.CommandButton Command3
Caption = "迭代格式3"
BeginProperty Font
Name = "宋体"
Size = 10.5
Charset = 134
Weight = 700
Underline = 0 'False
Italic = 0 'False
Strikethrough = 0 'False
EndProperty
Height = 495
Left = 4200
TabIndex = 2
Top = 240
Width = 1335
End
Begin VB.CommandButton Command2
Caption = "迭代格式2"
BeginProperty Font
Name = "宋体"
Size = 10.5
Charset = 134
Weight = 700
Underline = 0 'False
Italic = 0 'False
Strikethrough = 0 'False
EndProperty
Height = 495
Left = 2280
TabIndex = 1
Top = 240
Width = 1335
End
Begin VB.CommandButton Command1
Caption = "迭代格式1"
BeginProperty Font
Name = "宋体"
Size = 10.5
Charset = 134
Weight = 700
Underline = 0 'False
Italic = 0 'False
Strikethrough = 0 'False
EndProperty
Height = 495
Left = 360
TabIndex = 0
Top = 240
Width = 1335
End
End
Attribute VB_Name = "Form22"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = True
Attribute VB_Exposed = False
Private Sub Command1_Click()
x0 = Val(InputBox("输入迭代初值"))
Cls
Print: Print: Print: Print: Print: Print
Print Tab(10); "迭代格式:x=(2*x0+5)^(1/3)"
Print Tab(10); "迭代初值:x0="; x0
Print Tab(10); "迭代过程:"
k = 1
Do While True
x = (2 * x0 + 5) ^ (1 / 3)
Print Tab(10); "k="; k, "x="; Int(x * 1000000 + 0.5) / 1000000
e = Abs(x - x0)
MsgBox "按任意键继续"
If e < 0.00001 Then
Exit Do
End If
x0 = x
k = k + 1
Loop
Print
Print Tab(10); "经过"; k; "次迭代后得到方程的解为:"; "x="; Int(x * 1000000 + 0.5) / 1000000
End Sub
Private Sub Command2_Click()
x0 = Val(InputBox("输入迭代初值"))
k = 1
Cls
Print: Print: Print: Print: Print: Print
Print Tab(10); "迭代格式:x=sqr(2+5/x0)"
Print Tab(10); "迭代初值:x0="; x0
Print Tab(10); "迭代过程:"
Do While True
x = Sqr(2 + 5 / x0)
Print Tab(10); "k="; k, "x="; Int(x * 1000000 + 0.5) / 1000000
e = Abs(x - x0)
MsgBox "按任意键继续"
If e < 0.00001 Then
Exit Do
End If
x0 = x
k = k + 1
Loop
Print
Print Tab(10); "经过"; k; "次迭代后得到方程的解为:"; "x="; Int(x * 1000000 + 0.5) / 1000000
End Sub
Private Sub Command3_Click()
x0 = Val(InputBox("输入迭代初值"))
'f=x0^3-x0-5
k = 1
Cls
Print: Print: Print: Print: Print: Print
Print Tab(10); "迭代格式:x=x0^3-x0-5"
Print Tab(10); "迭代初值:x0="; x0
Print Tab(10); "迭代过程:"
Do While True
x = x0 ^ 3 - x0 - 5
Print Tab(10); "k="; k, "x="; Int(x * 1000000 + 0.5) / 1000000
e = Abs(x - x0)
MsgBox "按任意键继续"
If e < 0.00001 Then
Exit Do
End If
x0 = x
k = k + 1
Loop
Print
Print Tab(10); "经过"; k; "次迭代后得到方程的解为:"; "x="; Int(x * 1000000 + 0.5) / 1000000
End Sub
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