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align=bottom border=0></A> <BR><B>Next:</B> <A 
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name=tex2html975>Variance</A> <B>Up:</B> <A 
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name=tex2html971>Quality of Estimates</A> <B>Previous:</B> <A 
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<H4><A name=SECTION00315110000000000000>Bias </A></H4>: <BR>
<P></P>
<DIV align=center><!-- MATH \begin{displaymath}BIAS=E_F(\theta(F_n))-\theta(F)\end{displaymath} --><IMG 
height=37 
alt=\begin{displaymath}BIAS=E_F(\theta(F_n))-\theta(F)\end{displaymath} 
src="Bias.files/img311.png" width=199 border=0> </DIV><BR clear=all>
<P></P>If we take the statistic <!-- MATH $R({\cal X},F)= \theta(F_n)-\theta(F)$ --><IMG height=64 
alt="$R({\cal X},F)=&#10;\theta(F_n)-\theta(F)$" src="Bias.files/img312.png" 
width=455 align=middle border=0>, (where <IMG height=45 alt=$F_n$ 
src="Bias.files/img309.png" width=26 align=middle border=0> denotes the 
empirical distribution function) and apply the bootstrap algorithm to its 
expectation then we obtain the estimate : <BR>
<P></P>
<DIV align=center><!-- MATH \begin{displaymath}\widehat{BIAS}=E_*R^*=\frac{1}{B}\sum_{b=1}^B(\widehat{\theta}^{*b}-\widehat{\theta})=\widehat{\theta}^{*\bullet}-\widehat{\theta}\end{displaymath} --><IMG 
height=46 
alt="\begin{displaymath}&#10;\widehat{BIAS}=E_*R^*=&#10;\frac{1}{B}\sum_{b=1}^B(\widehat{\the...&#10;...widehat{\theta})&#10;=\widehat{\theta}^{*\bullet}-\widehat{\theta}&#10;\end{displaymath}" 
src="Bias.files/img313.png" width=141 border=0> </DIV><BR clear=all>
<P></P>where the dot indicates averaging :<!-- MATH $\widehat{\theta}^{*\bullet}=\sum_{b=1}^B\widehat{\theta}^{*b}/B$ --> 
<IMG height=70 
alt="$\widehat{\theta}^{*\bullet}=&#10;\sum_{b=1}^B\widehat{\theta}^{*b}/B$" 
src="Bias.files/img314.png" width=410 align=middle border=0> <BR><BR>
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<ADDRESS>Susan Holmes 2002-01-12 </ADDRESS></BODY></HTML>

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