2350.txt

北大ACM题目例程 详细的解答过程 程序实现 算法分析

#define debug 0
#include<stdio.h>
#include<string.h>
#include<math.h>
#include<stdlib.h>
#define NMAX 1002
int b[NMAX];
main()
{
#if debug 	
	freopen("in.txt","r",stdin);
	freopen("out.txt","w",stdout);
#endif
	int t,n;
	float sum;
	float aver;
	float man;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%d",&n);
		int i;
		sum=0;
		for(i=0;i<n;i++)
		{
			scanf("%d",&b[i]);
			sum+=b[i];
		}
		aver=sum/n;
		man=0;
		for(i=0;i<n;i++)
		{
			if(b[i]>aver)
				man=man+1;
		}
		printf("%.3f%%\n",man*100/n);
	}

#if debug
	fclose(stdin);
	fclose(stdout);
#endif;
	return 1;
}