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    <td width="11%">-2</td>    <td width="12%">←λ</td>  </tr></table><p> </p><table border="1" width="75%">  <tr>    <td width="11%">B</td>    <td width="11%">C<sub>B</sub></td>    <td width="11%">C→</td>    <td width="11%">3</td>    <td width="11%">6</td>    <td width="11%">2</td>    <td width="11%">0</td>    <td width="11%">0</td>    <td width="12%">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; </td>  </tr>  <tr>    <td width="11%"> </td>    <td width="11%"> </td>    <td width="11%">P<sub>0</sub></td>    <td width="11%">P<sub>1</sub></td>    <td width="11%">P<sub>2</sub></td>    <td width="11%"><p align="left">P<sub>3</sub></td>    <td width="11%"><p align="left">P<sub>4</sub></td>    <td width="11%"><p align="left">P<sub>5</sub></td>    <td width="12%"> </td>  </tr>  <tr>    <td width="11%"><p align="left">A<sub>1</sub></td>    <td width="11%">3</td>    <td width="11%">2/5</td>    <td width="11%">1</td>    <td width="11%">0</td>    <td width="11%">-1</td>    <td width="11%">3/5&nbsp; </td>    <td width="11%">-4/5</td>    <td width="12%"> </td>  </tr>  <tr>    <td width="11%">A<sub>2</sub></td>    <td width="11%">6</td>    <td width="11%">1/5</td>    <td width="11%">0</td>    <td width="11%">1</td>    <td width="11%">1</td>    <td width="11%">-1/5</td>    <td width="11%">3/5</td>    <td width="12%"> </td>  </tr>  <tr>    <td width="11%"> </td>    <td width="11%">z=12/5</td>    <td width="11%"> </td>    <td width="11%">0</td>    <td width="11%">0</td>    <td width="11%">-1</td>    <td width="11%"><p align="left">-3/5</td>    <td width="11%">-6/5</td>    <td width="12%">←λ</td>  </tr></table><p> </p><p>故最优解为x<sub>1</sub>=2/5,x<sub>2</sub>=1/5,目标函数z=12/5.</p><p><b>例2</b> maxz=x<sub>1</sub>+2x<sub>5</sub>-x<sub>6</sub>,</p><p>-(12/7)x<sub>1</sub>+(1/14)x<sub>2</sub>+(5/14)x<sub>3</sub>+x<sub>4</sub>=45/7</p><p>(1/7)x<sub>1</sub>-(3/14)x<sub>2</sub>-(1/14)x<sub>3</sub>+x<sub>5</sub>=5/7</p><p>-(3/7)x<sub>1</sub>+(1/7)x<sub>2</sub>-(2/7)x<sub>3</sub>+x<sub>6</sub>=6/7 </p><p>x<sub>1</sub>,…,x<sub>6</sub>≥0. </p><p>问题的单纯形表如下: </p><div align="left"><table border="1" width="85%">  <tr>    <td width="11%">B</td>    <td width="11%">C<sub>B</sub></td>    <td width="11%">C→</td>    <td width="10%">1</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">2</td>    <td width="10%">-1</td>    <td width="10%"> </td>  </tr>  <tr>    <td width="10%"> </td>    <td width="10%"> </td>    <td width="10%">P<sub>0</sub></td>    <td width="10%">P<sub>1</sub></td>    <td width="10%">P<sub>2</sub></td>    <td width="10%">P<sub>3</sub></td>    <td width="10%">P<sub>4</sub></td>    <td width="10%">P<sub>5</sub></td>    <td width="10%">P<sub>6</sub></td>    <td width="10%"> </td>  </tr>  <tr>    <td width="10%">A<sub>4</sub></td>    <td width="10%">0</td>    <td width="10%">45/7</td>    <td width="10%">-12/7</td>    <td width="10%">1/14</td>    <td width="10%">5/14</td>    <td width="10%">1</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">90</td>  </tr>  <tr>    <td width="10%">A<sub>5</sub></td>    <td width="10%">2</td>    <td width="10%">5/7</td>    <td width="10%">1/7</td>    <td width="10%">-3/14</td>    <td width="10%">-1/14</td>    <td width="10%">0</td>    <td width="10%">1</td>    <td width="10%">0</td>    <td width="10%"> </td>  </tr>  <tr>    <td width="10%">A<sub>6</sub></td>    <td width="10%">-1</td>    <td width="10%">6/7</td>    <td width="10%">-3/7</td>    <td width="10%">(1/7)</td>    <td width="10%">-2/7</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">1</td>    <td width="10%">(6)</td>  </tr>  <tr>    <td width="10%"> </td>    <td width="10%">z=4/7</td>    <td width="10%"> </td>    <td width="10%">2/7</td>    <td width="10%">4/7</td>    <td width="10%">-1/7</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">←λ</td>  </tr></table></div><p> </p><div align="left"><table border="1" width="85%">  <tr>    <td width="11%">B</td>    <td width="11%">C<sub>B</sub></td>    <td width="11%">C→</td>    <td width="10%">1</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">2</td>    <td width="10%">-1</td>    <td width="10%"> </td>  </tr>  <tr>    <td width="10%"> </td>    <td width="10%"> </td>    <td width="10%">P<sub>0</sub></td>    <td width="10%">P<sub>1</sub></td>    <td width="10%">P<sub>2</sub></td>    <td width="10%">P<sub>3</sub></td>    <td width="10%">P<sub>4</sub></td>    <td width="10%">P<sub>5</sub></td>    <td width="10%">P<sub>6</sub></td>    <td width="10%"> </td>  </tr>  <tr>    <td width="10%">A<sub>4</sub></td>    <td width="10%">0</td>    <td width="10%">6</td>    <td width="10%">-3/2</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">1/2</td>    <td width="10%">1</td>    <td width="10%">0</td>    <td width="10%">-1/2</td>  </tr>  <tr>    <td width="10%">A<sub>5</sub></td>    <td width="10%">2</td>    <td width="10%">2</td>    <td width="10%">-1/2</td>    <td width="10%">0</td>    <td width="10%">-1/2</td>    <td width="10%">0</td>    <td width="10%">1</td>    <td width="10%">3/2</td>    <td width="10%"> </td>  </tr>  <tr>    <td width="10%">A<sub>2</sub></td>    <td width="10%">0</td>    <td width="10%">6</td>    <td width="10%">-3</td>    <td width="10%">1</td>    <td width="10%">-2</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">7</td>    <td width="10%"> </td>  </tr>  <tr>    <td width="10%"> </td>    <td width="10%">z=4</td>    <td width="10%"> </td>    <td width="10%">2</td>    <td width="10%">0</td>    <td width="10%">1</td>    <td width="10%">0</td>    <td width="10%">0</td>    <td width="10%">-4</td>    <td width="10%">←λ</td>  </tr></table></div><p>由于c<sub>1</sub>-z<sub>1</sub>>0,但P<sub>1</sub>=( -3/2 , -1/2, -3)<sup>T</sup>,所有元素都为负数,故问题无解.</p><p><img src="6_5_7.gif"></p></body></html>

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