y_e_01.cpp

来自「Tianjin University Online Judge 的80多道题目 」· C++ 代码 · 共 29 行

// Homework ,28 Oct,2007
// Input n and a serial of number m1,m2......
// mi = 2^k*p,while p is a prime number.

#include<iostream>
using std::cout;
using std::cin;

int main()
{
  int n , m , i , k , p;

  cin >> n;

  for ( i = 1; i <= n; i++ )
    {
      cin >> m;

      for ( k = 0; m % 2 != 0; k++ );

      cout << k << m;
    }

  return 0;
}