📄 y_e_01.cpp
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// Homework ,28 Oct,2007// Input n and a serial of number m1,m2......// mi = 2^k*p,while p is a prime number.#include<iostream>using std::cout;using std::cin;int main(){ int n , m , i , k , p; cin >> n; for ( i = 1; i <= n; i++ ) { cin >> m; for ( k = 0; m % 2 != 0; k++ ); cout << k << m; } return 0;}
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