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📄 toj_2959.cpp

📁 Tianjin University Online Judge 的80多道题目 .
💻 CPP
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#include<cstdio>#include<cstring>#include<cstdlib>#define MAXNUM 100010int n , b , pOfB , a[ MAXNUM ];int nOfD[ 2 ][ 2 ][ MAXNUM ];int main(){    int i , j , k ,  larger , smaller , diff , num;    //    freopen( "toj_2959_in.txt" , "r" , stdin );//    freoepn( "toj_2959_out.txt" , "w" , stdout );    scanf( "%d%d" , &n , &b );    for( i = 0; i < n; i++ ){        scanf( "%d" , &a[ i ] );        if( a[ i ] == b )            pOfB = i;    }    memset( nOfD , 0 , sizeof( nOfD ) );    nOfD[ 0 ][ 0 ][ 0 ] = nOfD[ 1 ][ 0 ][ 0 ] = 1;    larger = 0;    smaller = 0;    for( i = pOfB - 1 ; i >= 0; i-- ){        if( a[ i ] > b )            larger++;        else            smaller++;        diff = larger - smaller;//        printf( "%d %d\n" , larger , smaller );        if( diff >= 0 )            nOfD[ 0 ][ 0 ][ diff ]++;        else            nOfD[ 0 ][ 1 ][ abs( diff ) ]++;    }    larger = 0;    smaller = 0;    for( i = pOfB + 1 ; i < n; i++ ){        if( a[ i ] > b )            larger++;        else            smaller++;        diff = larger - smaller;        if( diff >= 0 )            nOfD[ 1 ][ 0 ][ diff ]++;        else            nOfD[ 1 ][ 1 ][ abs( diff ) ]++;    }//     for( i = 0; i < 2; i++ ){//         for( j = 0; j < 2; j++ ){//             for( k = 0; k < n; k++ )//                 printf( "%d " , nOfD[ i ][ j ][ k ] );//             printf( "\n" );//         }//         printf( "\n" );//     }    for( num = 0 , i = 1; i < n; i++ )        for( j = 0; j < 2; j++ ){            num += nOfD[ 0 ][ j ][ i ] * nOfD[ 1 ][ 1 - j ][ i ];        }    num += nOfD[ 0 ][ 0 ][ 0 ] * nOfD[ 1 ][ 0 ][ 0 ];    printf( "%d\n" , num );//    system( "pause" );    return 0;}                                                            

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