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📄 coll6.c

📁 fortran并行计算包
💻 C
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/* -*- Mode: C; c-basic-offset:4 ; -*- *//* *  (C) 2001 by Argonne National Laboratory. *      See COPYRIGHT in top-level directory. */#include "mpi.h"#include <stdio.h>#define MAX_PROCESSES 10int main( int argc, char **argv ){    int              rank, size, i,j;    int              table[MAX_PROCESSES][MAX_PROCESSES];    int              errors=0;    int              participants;    int              displs[MAX_PROCESSES];    int              recv_counts[MAX_PROCESSES];    MPI_Init( &argc, &argv );    MPI_Comm_rank( MPI_COMM_WORLD, &rank );    MPI_Comm_size( MPI_COMM_WORLD, &size );    /* A maximum of MAX_PROCESSES processes can participate */    if ( size > MAX_PROCESSES ) participants = MAX_PROCESSES;    else              participants = size;    /* while (MAX_PROCESSES % participants) participants--; */    if (MAX_PROCESSES % participants) {	fprintf( stderr, "Number of processors must divide %d\n",		MAX_PROCESSES );	MPI_Abort( MPI_COMM_WORLD, 1 );	}    if ( (rank < participants) ) {      /* Determine what rows are my responsibility */      int block_size = MAX_PROCESSES / participants;      int begin_row  = rank * block_size;      int end_row    = (rank+1) * block_size;      int send_count = block_size * MAX_PROCESSES;            /* Fill in the displacements and recv_counts */      for (i=0; i<participants; i++) {	displs[i]      = i * block_size * MAX_PROCESSES;	recv_counts[i] = send_count;      }      /* Paint my rows my color */      for (i=begin_row; i<end_row ;i++)	for (j=0; j<MAX_PROCESSES; j++)	  table[i][j] = rank + 10;            /* Everybody gets the gathered data */      MPI_Allgatherv(&table[begin_row][0], send_count, MPI_INT, 		     &table[0][0], recv_counts, displs, 		     MPI_INT, MPI_COMM_WORLD);      /* Everybody should have the same table now.	 The entries are:	 Table[i][j] = (i/block_size) + 10;       */      for (i=0; i<MAX_PROCESSES;i++) 	if ( (table[i][0] - table[i][MAX_PROCESSES-1] !=0) ) 	  errors++;      for (i=0; i<MAX_PROCESSES;i++) {	  for (j=0; j<MAX_PROCESSES;j++) {	      if (table[i][j] != (i/block_size) + 10) errors++;	      }	  }      if (errors) {	  /* Print out table if there are any errors */	  for (i=0; i<MAX_PROCESSES;i++) {	      printf("\n");	      for (j=0; j<MAX_PROCESSES; j++)		  printf("  %d",table[i][j]);	      }	  printf("\n");	  }    }     MPI_Finalize();    if (errors)        printf( "[%d] done with ERRORS(%d)!\n", rank, errors );    else {	if (rank == 0) 	    printf(" No Errors\n");    }    return errors;}

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