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📄 coll5.c

📁 fortran并行计算包
💻 C
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/* -*- Mode: C; c-basic-offset:4 ; -*- *//* *  (C) 2001 by Argonne National Laboratory. *      See COPYRIGHT in top-level directory. */#include "mpi.h"#include <stdio.h>#define MAX_PROCESSES 10int main( int argc, char **argv ){    int              rank, size, i,j;    int              table[MAX_PROCESSES][MAX_PROCESSES];    int              row[MAX_PROCESSES];    int              errors=0;    int              participants;    int              displs[MAX_PROCESSES];    int              send_counts[MAX_PROCESSES];    MPI_Init( &argc, &argv );    MPI_Comm_rank( MPI_COMM_WORLD, &rank );    MPI_Comm_size( MPI_COMM_WORLD, &size );    /* A maximum of MAX_PROCESSES processes can participate */    if ( size > MAX_PROCESSES ) participants = MAX_PROCESSES;    else              participants = size;    if ( (rank < participants) ) {      int recv_count = MAX_PROCESSES;            /* If I'm the root (process 0), then fill out the big table */      /* and setup  send_counts and displs arrays */      if (rank == 0) 	for ( i=0; i<participants; i++) {	  send_counts[i] = recv_count;	  displs[i] = i * MAX_PROCESSES;	  for ( j=0; j<MAX_PROCESSES; j++ ) 	    table[i][j] = i+j;	}            /* Scatter the big table to everybody's little table */      MPI_Scatterv(&table[0][0], send_counts, displs, MPI_INT, 		   &row[0]     , recv_count, MPI_INT, 0, MPI_COMM_WORLD);      /* Now see if our row looks right */      for (i=0; i<MAX_PROCESSES; i++) 	if ( row[i] != i+rank ) errors++;    }     MPI_Finalize();    if (errors)        printf( "[%d] done with ERRORS(%d)!\n", rank, errors );    else {	if (rank == 0) 	    printf(" No Errors\n");	}    return errors;}

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