📄 soln2_2.cpp
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// Soln2_2.cpp
#include <iostream>
using std::cin;
using std::cout;
using std::endl;
/*
Shifting number right 3 positions with the expression (number >> 3) divides the value by 8 and discards the remainder.
Shifting the result of the previous operation left by 3 positions with the expression ((number >> 3) << 3) multiplies
it by 8 so you get the value of number less the remainder R after dividing by 8 i.e. (number - R)
Subtracting (number - R) from number gives just R, which is what you are looking for.
*/
int main()
{
int number;
cout << "Enter a number: ";
cin >> number;
cout << "Thank you. The remainder after dividing your number by 8 is "
<< number - ((number >> 3) << 3);
cout << endl;
return 0;
}
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