ac1239.pas

来自「同济大学 Online在线题库 AC源代码合集 程序设计竞赛必看资料」· PAS 代码 · 共 44 行

program tju1239;
var
  p,q:ansistring;
  n,u,lp,lq,l,i,pp,pq,count:word;
function match(sp,sq,l:word):boolean;
  var
    i:word;
  begin
    for i:=1 to l do
      if (p[sp+i]<>'?') and (q[sq+i]<>'?') and (p[sp+i]<>q[sq+i]) then begin
        match:=false;exit;
      end;
    match:=true;
  end;
begin
  repeat
    readln(p);lp:=length(p);
    readln(n);count:=0;
    if pos('*',p)=0 then
      for u:=1 to n do begin
        readln(q);lq:=length(q);
        if (lp=lq) and match(0,0,lp) then inc(count);
      end
    else
      for u:=1 to n do begin
        readln(q);lq:=length(q);
        pp:=pos('*',p);
        if (lq<pp-1) or not match(0,0,pp-1) then continue;
        pq:=pp-1;
        for i:=pp+1 to lp do
          if p[i]='*' then begin
            l:=i-pp-1;
            while pq+l<=lq do
              if match(pp,pq,l) then break else inc(pq);
            if pq+l>lq then break;
            pp:=i;inc(pq,l);
          end;
        l:=lp-pp;
        if (pq+l<=lq) and match(pp,lq-l,l) then inc(count);
      end;
    writeln(n-count);
  until seekeof;
end.