ac1003.pas

同济大学 Online在线题库 AC源代码合集 程序设计竞赛必看资料

program tju1003;
var
  n,i,j:byte;
begin
  read(n);
  for i:=1 to n do begin
    for j:=1 to n-i do write(' ');
    for j:=1 to i*2-1 do write(chr(64+i));
    writeln;
  end;
end.