commentblock.sh
来自「一本完整的描述Unix Shell 编程的工具书的所有范例」· Shell 代码 · 共 31 行
SH
31 行
#!/bin/bash# commentblock.sh: <<COMMENTBLOCKecho "This line will not echo."This is a comment line missing the "#" prefix.This is another comment line missing the "#" prefix.&*@!!++=The above line will cause no error message,because the Bash interpreter will ignore it.COMMENTBLOCKecho "Exit value of above \"COMMENTBLOCK\" is $?." # 0# No error shown.# The above technique also comes in useful for commenting out#+ a block of working code for debugging purposes.# This saves having to put a "#" at the beginning of each line,#+ then having to go back and delete each "#" later.: <<DEBUGXXXfor file in *do cat "$file"doneDEBUGXXXexit 0
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