异步8421bcd计数器.ewb

Multisim2001软件的仿真电路实例261例

Electronics Workbench Circuit File
Version: 5
Charset: ANSI
Description: 
"        如图所示，它是由4个JK触发器构成的异步8421BCD计数器。" 
"        若初始状态Q^n4Q^n3Q^n2Q^n1=0000，在CP脉冲作用下Q^n+1=1，Q1为上跳使后3级触发器都保持不变。再将0001作为当前状态，第二个CP脉冲使Q^n+11=0，Q1的下降沿送到CP2和CP4处。J2=Q^n4反=1，K2=1则Q^n+12=1，Q2上跳使Q3保持不变，而J4=1，K4=1，因此Q1下跳使Q4置0也不变，状态变为0010。" 
"        当Q^n4Q^n3Q^n2Q^n1=1001时，CP的作用使Q^n+1=0，Q1由1变0使CP2和CP4下跳，此时J2=Q4=0，J4=0，K4=0，则Q2保持0不变，而Q4由1变为0状态，Q2状态不变使Q3也保持不变，其下一状态为0000回到初始状态。由状态表可见电路实现了8421BCD计数。" 
"         异步8421BCD计数器状态转移表：序号	Q4	Q3	Q2	Q1" 
"				  0	  0	  0	  0	  0" 
"				  1	  0	  0	  0	  1" 
"				  2	  0	  0	  1	  0" 
"				  3	  0	  0	  1	  1" 
"				  4	  0	  1	  0	  0" 
"				  5	  0	  1	  0	  1" 
"				  6	  0	  1	  1	  0	" 
"				  7	  0	  1	  1	  1" 
"				  8	  1	  0	  0	  0" 
"				  9	  1	  0	  0	  1" 

EncryptionType: 2
UsingVectorGraphics: 0
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