⭐ 欢迎来到虫虫下载站! | 📦 资源下载 📁 资源专辑 ℹ️ 关于我们
⭐ 虫虫下载站

📄 porterstemmer.java

📁 Lucene a java open-source SearchEngine Framework
💻 JAVA
字号:
package org.apache.lucene.analysis;/** * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements.  See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License.  You may obtain a copy of the License at * *     http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. *//*   Porter stemmer in Java. The original paper is in       Porter, 1980, An algorithm for suffix stripping, Program, Vol. 14,       no. 3, pp 130-137,   See also http://www.tartarus.org/~martin/PorterStemmer/index.html   Bug 1 (reported by Gonzalo Parra 16/10/99) fixed as marked below.   Tthe words 'aed', 'eed', 'oed' leave k at 'a' for step 3, and b[k-1]   is then out outside the bounds of b.   Similarly,   Bug 2 (reported by Steve Dyrdahl 22/2/00) fixed as marked below.   'ion' by itself leaves j = -1 in the test for 'ion' in step 5, and   b[j] is then outside the bounds of b.   Release 3.   [ This version is derived from Release 3, modified by Brian Goetz to     optimize for fewer object creations.  ]*/import java.io.*;/** * * Stemmer, implementing the Porter Stemming Algorithm * * The Stemmer class transforms a word into its root form.  The input * word can be provided a character at time (by calling add()), or at once * by calling one of the various stem(something) methods. */class PorterStemmer{  private char[] b;  private int i,    /* offset into b */    j, k, k0;  private boolean dirty = false;  private static final int INC = 50; /* unit of size whereby b is increased */  private static final int EXTRA = 1;  public PorterStemmer() {    b = new char[INC];    i = 0;  }  /**   * reset() resets the stemmer so it can stem another word.  If you invoke   * the stemmer by calling add(char) and then stem(), you must call reset()   * before starting another word.   */  public void reset() { i = 0; dirty = false; }  /**   * Add a character to the word being stemmed.  When you are finished   * adding characters, you can call stem(void) to process the word.   */  public void add(char ch) {    if (b.length <= i + EXTRA) {      char[] new_b = new char[b.length+INC];      System.arraycopy(b, 0, new_b, 0, b.length);      b = new_b;    }    b[i++] = ch;  }  /**   * After a word has been stemmed, it can be retrieved by toString(),   * or a reference to the internal buffer can be retrieved by getResultBuffer   * and getResultLength (which is generally more efficient.)   */  public String toString() { return new String(b,0,i); }  /**   * Returns the length of the word resulting from the stemming process.   */  public int getResultLength() { return i; }  /**   * Returns a reference to a character buffer containing the results of   * the stemming process.  You also need to consult getResultLength()   * to determine the length of the result.   */  public char[] getResultBuffer() { return b; }  /* cons(i) is true <=> b[i] is a consonant. */  private final boolean cons(int i) {    switch (b[i]) {    case 'a': case 'e': case 'i': case 'o': case 'u':      return false;    case 'y':      return (i==k0) ? true : !cons(i-1);    default:      return true;    }  }  /* m() measures the number of consonant sequences between k0 and j. if c is     a consonant sequence and v a vowel sequence, and <..> indicates arbitrary     presence,          <c><v>       gives 0          <c>vc<v>     gives 1          <c>vcvc<v>   gives 2          <c>vcvcvc<v> gives 3          ....  */  private final int m() {    int n = 0;    int i = k0;    while(true) {      if (i > j)        return n;      if (! cons(i))        break;      i++;    }    i++;    while(true) {      while(true) {        if (i > j)          return n;        if (cons(i))          break;        i++;      }      i++;      n++;      while(true) {        if (i > j)          return n;        if (! cons(i))          break;        i++;      }      i++;    }  }  /* vowelinstem() is true <=> k0,...j contains a vowel */  private final boolean vowelinstem() {    int i;    for (i = k0; i <= j; i++)      if (! cons(i))        return true;    return false;  }  /* doublec(j) is true <=> j,(j-1) contain a double consonant. */  private final boolean doublec(int j) {    if (j < k0+1)      return false;    if (b[j] != b[j-1])      return false;    return cons(j);  }  /* cvc(i) is true <=> i-2,i-1,i has the form consonant - vowel - consonant     and also if the second c is not w,x or y. this is used when trying to     restore an e at the end of a short word. e.g.          cav(e), lov(e), hop(e), crim(e), but          snow, box, tray.  */  private final boolean cvc(int i) {    if (i < k0+2 || !cons(i) || cons(i-1) || !cons(i-2))      return false;    else {      int ch = b[i];      if (ch == 'w' || ch == 'x' || ch == 'y') return false;    }    return true;  }  private final boolean ends(String s) {    int l = s.length();    int o = k-l+1;    if (o < k0)      return false;    for (int i = 0; i < l; i++)      if (b[o+i] != s.charAt(i))        return false;    j = k-l;    return true;  }  /* setto(s) sets (j+1),...k to the characters in the string s, readjusting     k. */  void setto(String s) {    int l = s.length();    int o = j+1;    for (int i = 0; i < l; i++)      b[o+i] = s.charAt(i);    k = j+l;    dirty = true;  }  /* r(s) is used further down. */  void r(String s) { if (m() > 0) setto(s); }  /* step1() gets rid of plurals and -ed or -ing. e.g.           caresses  ->  caress           ponies    ->  poni           ties      ->  ti           caress    ->  caress           cats      ->  cat           feed      ->  feed           agreed    ->  agree           disabled  ->  disable           matting   ->  mat           mating    ->  mate           meeting   ->  meet           milling   ->  mill           messing   ->  mess           meetings  ->  meet  */  private final void step1() {    if (b[k] == 's') {      if (ends("sses")) k -= 2;      else if (ends("ies")) setto("i");      else if (b[k-1] != 's') k--;    }    if (ends("eed")) {      if (m() > 0)        k--;    }    else if ((ends("ed") || ends("ing")) && vowelinstem()) {      k = j;      if (ends("at")) setto("ate");      else if (ends("bl")) setto("ble");      else if (ends("iz")) setto("ize");      else if (doublec(k)) {        int ch = b[k--];        if (ch == 'l' || ch == 's' || ch == 'z')          k++;      }      else if (m() == 1 && cvc(k))        setto("e");    }  }  /* step2() turns terminal y to i when there is another vowel in the stem. */  private final void step2() {    if (ends("y") && vowelinstem()) {      b[k] = 'i';      dirty = true;    }  }  /* step3() maps double suffices to single ones. so -ization ( = -ize plus     -ation) maps to -ize etc. note that the string before the suffix must give     m() > 0. */  private final void step3() {    if (k == k0) return; /* For Bug 1 */    switch (b[k-1]) {    case 'a':      if (ends("ational")) { r("ate"); break; }      if (ends("tional")) { r("tion"); break; }      break;    case 'c':      if (ends("enci")) { r("ence"); break; }      if (ends("anci")) { r("ance"); break; }      break;    case 'e':      if (ends("izer")) { r("ize"); break; }      break;    case 'l':      if (ends("bli")) { r("ble"); break; }      if (ends("alli")) { r("al"); break; }      if (ends("entli")) { r("ent"); break; }      if (ends("eli")) { r("e"); break; }      if (ends("ousli")) { r("ous"); break; }      break;    case 'o':      if (ends("ization")) { r("ize"); break; }      if (ends("ation")) { r("ate"); break; }      if (ends("ator")) { r("ate"); break; }      break;    case 's':      if (ends("alism")) { r("al"); break; }      if (ends("iveness")) { r("ive"); break; }      if (ends("fulness")) { r("ful"); break; }      if (ends("ousness")) { r("ous"); break; }      break;    case 't':      if (ends("aliti")) { r("al"); break; }      if (ends("iviti")) { r("ive"); break; }      if (ends("biliti")) { r("ble"); break; }      break;    case 'g':      if (ends("logi")) { r("log"); break; }    }  }  /* step4() deals with -ic-, -full, -ness etc. similar strategy to step3. */  private final void step4() {    switch (b[k]) {    case 'e':      if (ends("icate")) { r("ic"); break; }      if (ends("ative")) { r(""); break; }      if (ends("alize")) { r("al"); break; }      break;    case 'i':      if (ends("iciti")) { r("ic"); break; }      break;    case 'l':      if (ends("ical")) { r("ic"); break; }      if (ends("ful")) { r(""); break; }      break;    case 's':      if (ends("ness")) { r(""); break; }      break;    }  }  /* step5() takes off -ant, -ence etc., in context <c>vcvc<v>. */  private final void step5() {    if (k == k0) return; /* for Bug 1 */    switch (b[k-1]) {    case 'a':      if (ends("al")) break;      return;    case 'c':      if (ends("ance")) break;      if (ends("ence")) break;      return;    case 'e':      if (ends("er")) break; return;    case 'i':      if (ends("ic")) break; return;    case 'l':      if (ends("able")) break;      if (ends("ible")) break; return;    case 'n':      if (ends("ant")) break;      if (ends("ement")) break;      if (ends("ment")) break;      /* element etc. not stripped before the m */      if (ends("ent")) break;      return;    case 'o':      if (ends("ion") && j >= 0 && (b[j] == 's' || b[j] == 't')) break;      /* j >= 0 fixes Bug 2 */      if (ends("ou")) break;      return;      /* takes care of -ous */    case 's':      if (ends("ism")) break;      return;    case 't':      if (ends("ate")) break;      if (ends("iti")) break;      return;    case 'u':      if (ends("ous")) break;      return;    case 'v':      if (ends("ive")) break;      return;    case 'z':      if (ends("ize")) break;      return;    default:      return;    }    if (m() > 1)      k = j;  }  /* step6() removes a final -e if m() > 1. */  private final void step6() {    j = k;    if (b[k] == 'e') {      int a = m();      if (a > 1 || a == 1 && !cvc(k-1))        k--;    }    if (b[k] == 'l' && doublec(k) && m() > 1)      k--;  }  /**   * Stem a word provided as a String.  Returns the result as a String.   */  public String stem(String s) {    if (stem(s.toCharArray(), s.length()))      return toString();    else      return s;  }  /** Stem a word contained in a char[].  Returns true if the stemming process   * resulted in a word different from the input.  You can retrieve the   * result with getResultLength()/getResultBuffer() or toString().   */  public boolean stem(char[] word) {    return stem(word, word.length);  }  /** Stem a word contained in a portion of a char[] array.  Returns   * true if the stemming process resulted in a word different from   * the input.  You can retrieve the result with   * getResultLength()/getResultBuffer() or toString().   */  public boolean stem(char[] wordBuffer, int offset, int wordLen) {    reset();    if (b.length < wordLen) {      char[] new_b = new char[wordLen + EXTRA];      b = new_b;    }    System.arraycopy(wordBuffer, offset, b, 0, wordLen);    i = wordLen;    return stem(0);  }  /** Stem a word contained in a leading portion of a char[] array.   * Returns true if the stemming process resulted in a word different   * from the input.  You can retrieve the result with   * getResultLength()/getResultBuffer() or toString().   */  public boolean stem(char[] word, int wordLen) {    return stem(word, 0, wordLen);  }  /** Stem the word placed into the Stemmer buffer through calls to add().   * Returns true if the stemming process resulted in a word different   * from the input.  You can retrieve the result with   * getResultLength()/getResultBuffer() or toString().   */  public boolean stem() {    return stem(0);  }  public boolean stem(int i0) {    k = i - 1;    k0 = i0;    if (k > k0+1) {      step1(); step2(); step3(); step4(); step5(); step6();    }    // Also, a word is considered dirty if we lopped off letters    // Thanks to Ifigenia Vairelles for pointing this out.    if (i != k+1)      dirty = true;    i = k+1;    return dirty;  }  /** Test program for demonstrating the Stemmer.  It reads a file and   * stems each word, writing the result to standard out.   * Usage: Stemmer file-name   */  public static void main(String[] args) {    PorterStemmer s = new PorterStemmer();    for (int i = 0; i < args.length; i++) {      try {        InputStream in = new FileInputStream(args[i]);        byte[] buffer = new byte[1024];        int bufferLen, offset, ch;        bufferLen = in.read(buffer);        offset = 0;        s.reset();        while(true) {          if (offset < bufferLen)            ch = buffer[offset++];          else {            bufferLen = in.read(buffer);            offset = 0;            if (bufferLen < 0)              ch = -1;            else              ch = buffer[offset++];          }          if (Character.isLetter((char) ch)) {            s.add(Character.toLowerCase((char) ch));          }          else {             s.stem();             System.out.print(s.toString());             s.reset();             if (ch < 0)               break;             else {               System.out.print((char) ch);             }           }        }        in.close();      }      catch (IOException e) {        System.out.println("error reading " + args[i]);      }    }  }}

⌨️ 快捷键说明

复制代码 Ctrl + C
搜索代码 Ctrl + F
全屏模式 F11
切换主题 Ctrl + Shift + D
显示快捷键 ?
增大字号 Ctrl + =
减小字号 Ctrl + -