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来自「对实验板上 EEPROM 器件 AT24C08 进行读写访问。实现从同一地址写入」· A 代码 · 共 80 行

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;**********OPTIONS*******************************
_RAM_STARTADDRESS   EQU   0xc000000
_ISR_STARTADDRESS   EQU   0xc7fff00 ;GCS6:64M DRAM/SDRAM
;_ISR_STARTADDRESS  EQU   0xc1fff00 ;GCS6:16M DRAM


;BUSWIDTH; 16,32
                GBLA    BUSWIDTH
BUSWIDTH	       SETA    16


;"DRAM","SDRAM"
                GBLS    BDRAMTYPE
;BDRAMTYPE       SETS    "DRAM"
BDRAMTYPE       SETS    "SDRAM"



;This value has to be TRUE on ROM program.
;This value has to be FALSE in RAM program.
                GBLL    PLLONSTART
PLLONSTART      SETL    {TRUE}

	GBLA	PLLCLK
PLLCLK		SETA	60000000


	[	PLLCLK = 30000000	
M_DIV	EQU	0x43	;Fin=8MHz Fout=30MHz
P_DIV	EQU	0x3
S_DIV	EQU	0x2		
	]


	[	PLLCLK = 40000000	
;M_DIV	EQU	0x48	;Fin=10MHz Fout=40MHz
;P_DIV	EQU	0x3
;S_DIV	EQU	0x2		
M_DIV	EQU	0x60	;Fin=8MHz Fout=40MHz
P_DIV	EQU	0x3
S_DIV	EQU	0x2		
	]

	[	PLLCLK = 50000000	
M_DIV	EQU	0x2a	;Fin=10MHz Fout=50MHz
P_DIV	EQU	0x3
S_DIV	EQU	0x1	
	]

	[	PLLCLK = 60000000	
;M_DIV	EQU	0x34	;Fin=10MHz Fout=60MHz
;P_DIV	EQU	0x3
;S_DIV	EQU	0x1
;M_DIV	EQU	0x45	;Fin=8MHz Fout=60MHz
;P_DIV	EQU	0x3
;S_DIV	EQU	0x1
M_DIV	EQU	0x48	;Fin=6MHz Fout=60MHz
P_DIV	EQU	0x2
S_DIV	EQU	0x1
;M_DIV	EQU	0x34	;Fin=4MHz Fout=60MHz
;P_DIV	EQU	0x0
;S_DIV	EQU	0x1
;M_DIV	EQU	0x48	;Fin=3MHz Fout=60MHz
;P_DIV	EQU	0x0
;S_DIV	EQU	0x1
	]

	[	PLLCLK = 66000000	
M_DIV	EQU	0x3a	;Fin=10MHz Fout=75MHz
P_DIV	EQU	0x3
S_DIV	EQU	0x1		
	]

	[	PLLCLK = 75000000	
M_DIV	EQU	0x43	;Fin=10MHz Fout=75MHz
P_DIV	EQU	0x3
S_DIV	EQU	0x1		
	]
;************************************************
	END

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