📄 ex6.c
字号:
#include <stdio.h>#include <math.h>#include <stdlib.h>#include "math_util.h"/* This problem is from Bryson, A. and Ho, Y., Applied Optimal Control, pages 52-55 Minimum drag nose shape in hypersonic flow */main(){ FILE *output_file; int n, m, ms, i, j, ierr; long double tend, y0, y1, y2, y3, z0, **yout, **zout, *time, tol, T, dt, x; void dyn( long double *, long double *, long double *, long double * ); void dynbc( long double *, long double *, long double * ); int mshoot_dae( long double **, long double **, long double *, int, int, int, long double, void(*)(), void(*)(), void(*)(), void(*)() ); void dynjac( long double *, long double *, long double **, long double **, long double **, long double ** ); void dyndbc( long double *, long double *, long double **, long double ** ); n = 2; m = 1; ms = 101; time = a1d_allo_dbl( ms ); yout = a2d_allo_dbl( ms, n ); zout = a2d_allo_dbl( ms, m ); tol = 1.0e-4; tend = 4.0; output_file = fopen("ex6.dat","w"); if( output_file == NULL ) { printf("ERROR unable to open output file\n"); exit(1); }/* Setup initial guess*/ y0 = 1; y1 = 0.25; z0 = 0.3; T = tend; dt = 1.0/(ms-1); for( i = 0; i < ms; i++ ) { x = pow(10.0,i*dt); time[ms-1-i]=T+T*(1.0-x)/9.0; } for( i = 0; i < ms; i++ ) { yout[i][0] = y0; yout[i][1] = y1; zout[i][0] = z0; printf("%Le %Le %Le %Le\n",time[i],yout[i][0],yout[i][1],zout[i][0]); } ierr = mshoot_dae( yout, zout, time, n, m, ms, tol, dyn, dynjac, dynbc, dyndbc ); x = zout[0][0]; dt = 3.0+10.0*x*x+17.0*x*x*x*x+2.0*x*x*x*x*x*x+4.0*x*x*x*x*log(1.0/x); dt *= (x*x)/((1.0+x*x)*(1.0+x*x)*(1.0+x*x)*(1.0+x*x)); printf("Cd = %Le\n",dt); /* Coefficient of drag */ for( i = 0; i < ms; i++ ) { fprintf(output_file,"%Le\t",time[i]); for( j = 0; j < n; j++ ) fprintf(output_file,"%Le\t",yout[i][j]); for( j = 0; j < m; j++ ) fprintf(output_file,"%Le\t",zout[i][j]); dt = 2.0*yout[i][0]*zout[i][0]; dt *= zout[i][0]*zout[i][0]; dt /= ((1.0+zout[i][0]*zout[i][0])*(1.0+zout[i][0]*zout[i][0])); dt *= -1.0; fprintf(output_file,"%Le\t",dt); fprintf(output_file,"\n"); } fclose( output_file ); exit(0);}void dynbc( sy0, syms, r )long double *sy0, *syms, *r;{ r[0] = sy0[0]-1.0; r[1] = syms[1]-syms[0];}void dyndbc( sy0, syms, a, b )long double *sy0, *syms, **a, **b;{ void mat_null( long double **, int, int ); mat_null( a, 2, 2 ); mat_null( b, 2, 2 ); a[0][0] = 1.0; b[1][0] = -1.0; b[1][1] = 1.0;}void dyn( y, z, f, g )long double *y, *z, *f, *g;{ long double u; u = z[0]; f[0] = -u; f[1] = -(u*u*u)/(1.0+u*u); g[0] = (y[0]*u*u*(3.0+u*u))/((1.0+u*u)*(1.0+u*u)) - y[1];}void dynjac( y, z, fy, fz, gy, gz )long double *y, *z, **fy, **fz, **gy, **gz;{ void mat_null( long double **, int, int ); int n = 2, m = 1; long double u, d; u = z[0]; d = 1.0+u*u; mat_null( fy, n, n ); mat_null( fz, n, m ); mat_null( gy, m, n ); mat_null( gz, m, m ); fz[0][0] = -1.0; fz[1][0] = -3.0*u*u/(1.0+u*u) + (2.0*u*u*u*u)/(d*d); gy[0][0] = (u*u*(3.0+u*u))/(d*d); gy[0][1] = -1.0; gz[0][0] = (2.0*y[0]*u*(3.0+u*u))/(d*d) + (2.0*y[0]*u*u*u)/(d*d) - (4.0*y[0]*u*u*u*(3.0+u*u))/(d*d*d);}
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -