📄 ip_06_03.m
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% MATLAB script for Illustrative Problem 6.3.
echo on
f_cutoff=2000; % the desired cutoff frequency
f_stopband=2500; % the actual stopband frequency
fs=10000; % the sampling frequency
f1=2*f_cutoff/fs; % the normalized passband frequency
f2=2*f_stopband/fs; % the normalized stopband frequency
N=41; % This number is found by experiment.
F=[0 f1 f2 1];
M=[1 1 0 0]; % describes the lowpass filter
B=remez(N-1,F,M); % returns the FIR tap coefficients
% Plotting command follows.
figure(1);
[H,W]=freqz(B);
H_in_dB=20*log10(abs(H));
plot(W/(2*pi),H_in_dB);
figure(2);
plot(W/(2*pi),(180/pi)*unwrap(angle(H)));
% Plot of the impulse response follows.
figure(3);
plot(zeros(size([0:N-1])));
hold;
stem([0:N-1],B);
c=N;
title(['N is ',num2str(c)])
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