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📄 parse.cpp

📁 2003年机器人足球世界杯2D仿真组冠军的源程序。在此程序的基础上诞生了一批很强的球队。如2007年国内亚军的合肥工业大学代表队就是在此基础上发展起来的
💻 CPP
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/*Copyright (c) 2000-2003, Jelle Kok, University of AmsterdamAll rights reserved.Redistribution and use in source and binary forms, with or withoutmodification, are permitted provided that the following conditions are met:1. Redistributions of source code must retain the above copyright notice, thislist of conditions and the following disclaimer.2. Redistributions in binary form must reproduce the above copyright notice,this list of conditions and the following disclaimer in the documentationand/or other materials provided with the distribution.3. Neither the name of the University of Amsterdam nor the names of itscontributors may be used to endorse or promote products derived from thissoftware without specific prior written permission.THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THEIMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE AREDISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR CONTRIBUTORS BE LIABLEFOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIALDAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS ORSERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVERCAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY,OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USEOF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.*//*! \file Parse.cpp<pre><b>File:</b>          Parse.cpp<b>Project:</b>       Robocup Soccer Simulation Team: UvA Trilearn<b>Authors:</b>       Jelle Kok<b>Created:</b>       12/02/2001<b>Last Revision:</b> $ID$<b>Contents:</b>      class declarations of Parse class that can be used to               quickly parse specific string messages.<hr size=2><h2><b>Changes</b></h2><b>Date</b>             <b>Author</b>          <b>Comment</b>12/02/2001       Jelle Kok       Initial version created</pre>*/#include "Parse.h"#include <ctype.h>    // needed for isdigit#include <math.h>     // needed for pow#include <string.h>   // needed for strlen/*****************************************************************************//********************** CLASS PARSE ******************************************//*****************************************************************************//*! This method walks through the string starting at the character where strMsg    points to and stops when or the end of the string is reached or a non space    is reached. strMsg is updated to this new position.    \param strMsg pointer to a character in a string array    \return character that is at the first non space, '\0' when end of string    is reached. */char Parse::gotoFirstNonSpace( char** strMsg ){  while(*strMsg && isspace(**strMsg) )    (*strMsg)++;  return  (*strMsg) ?  **strMsg : '\0';}/*! This method walks through the string starting at the character where strMsg    points to and stops when<BR>    - the end of the string is reached<BR>    - a character different than ' ' and ')' is read<BR>    strMsg is changed after this method is called.    \param strMsg pointer to a character in a string array    \return first character that is not equal to ' ' or ')', '\0' when string            didn't contain such a character. */char Parse::gotoFirstSpaceOrClosingBracket( char** strMsg ){  while( *strMsg && **strMsg!=' ' && **strMsg!=')' )    (*strMsg)++;  return  (*strMsg) ?  **strMsg : '\0';}/*! This method walks through the string starting at the character where strMsg    points to and stops when the character c is reached. strMsg is changed    after this method is called..    \param c character that is searched for in strMsg.    \param strMsg pointer to a character in a string array    \return number of character skipped to reach c, -1 when not found */int Parse::gotoFirstOccurenceOf( char c, char** strMsg ){  int i=0;  while(**strMsg && **strMsg != c )  {    i++;    (*strMsg)++;  }  if( ! **strMsg )    return -1;  return i;}/*! This method walks through the string starting at the character where strMsg    points to and returns the first integer that can be read from this string.    Any other characters in front of this integer are discarded. After this    method is returned, strMsg points to the first character after the final    value of the integer.    \param strMsg pointer to a character in a string array    \return first integer that can be read from this string. */int Parse::parseFirstInt( char** strMsg ){  int  iRes  = 0;  bool bIsMin= false;  char *str  = *strMsg;  while( *str != '\0' && !isdigit(*str) && *str!='-')    str++;                             // walk to first non digit or minus sign  if( *str != '\0' && *str=='-')       // if it was a minus sign, remember  {    bIsMin=true;    str++;  }  while( *str != '\0' && *str<='9' && *str>='0' )   // for all digits  {      iRes=iRes*10+(int)(*str-'0');                 // multiply old res with 10      str++;                                        // and add new value  }  *strMsg = str;  return (bIsMin) ? -iRes : iRes;}/*! This method walks through the string starting at the character where strMsg    points to and returns the first double that can be read from this string.    Any other characters in front of this integer are discarded. After this    method is returned, strMsg points to the first character after the final    value of the double. 4e-3, and NaN or nan are also recognized. When input    contains NaN or nan, -1000.0 is returned.    \param strMsg pointer to a character in a string array    \return first double that can be read from this string. */double Parse::parseFirstDouble( char** strMsg ){  double dRes=0.0, dFrac=1.0;  bool bIsMin=false, bInDecimal=false, bCont=true;  char *str = *strMsg;  // go to first part of double (digit, minus sign or '.')  while( *str != '\0' && !isdigit(*str) && *str!='-' && *str!='.')  {    // when NaN or nan is double value, return -1000.0    if( (*str=='N' && strlen(str)>3 && *(str+1)=='a' && *(str+2)=='N') ||        (*str=='n' && strlen(str)>3 && *(str+1)=='a' && *(str+2)=='n') )    {      *strMsg = str+3;      return -1000.0;    }    else       str++;  }  if( *str != '\0' && *str=='-')               // if minus sign, remember that  {    bIsMin=true;    str++;  }  while( *str != '\0' && bCont)                // process the number bit by bit  {    if( *str=='.' )                            // in decimal part after '.'      bInDecimal = true;    else if( bInDecimal && *str<='9' && *str>='0') // number and in decimal    {      dFrac=dFrac*10.0;                        // shift decimal part to right      dRes += (double)(*str-'0')/dFrac;        // and add number    }    else if( *str<='9' && *str>='0' )          // if number and not decimal      dRes=dRes*10+(double)(*str-'0');         // shift left and add number    else if( *str=='e' ) // 10.6e-08           // if to power e    {      if( *(str+1) == '+' )                    // determine sign        dRes *=  pow(10, parseFirstInt(&str)); // and multiply with power      else if( *(str+1) == '-' )      {        str = str+2;                           // skip -        dRes /=  pow(10, parseFirstInt(&str)); // and divide by power      }      bCont = false;                           // after 'e' stop    }    else      bCont = false;                           // all other cases stop    if( bCont == true )                        // update when not stopped yet      str++;  }  *strMsg = str;  return (bIsMin && dRes != 0.0) ? -dRes : dRes;}/*****************************************************************************//********************* TESTING PURPOSES **************************************//*****************************************************************************//*#include<iostream.h>int main( void ){  double d = 13.6e+15;  char str[] = "13.6e+15";  double d2 = 13.6e-15;  char str2[] = "13.6e-15";  char *strmsg;  strmsg = &str[0];  cout  << d << endl;  cout << Parse::parseFirstDouble( &strmsg )<< endl;  strmsg = &str2[0];  cout  << d2 << endl;  cout << Parse::parseFirstDouble( &strmsg ) << endl;  return 0;}*/

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