exp.c

OMAP1030 处理器的ARM 侧硬件测试代码 OMAP1030 是TI的双核处理器

/****************************************************************************/
/*  exp    v2.24                                                           */
/*  Copyright (c) 1995-2002 Texas Instruments Incorporated                  */
/****************************************************************************/
#include <math.h>
#include <values.h>
#include <errno.h>

/****************************************************************************/
/*  EXP() - e ^ x							    */
/*									    */
/*  Based on the algorithm from "Software Manual for the Elementary         */
/*  Functions", Cody and Waite, Prentice Hall 1980, chapter 6.              */
/*									    */
/*  N = round(x / ln(2))						    */
/*  g = x - N * ln(2)							    */
/*  z = g * g								    */
/*									    */
/*  R = polynomial expansion						    */
/*									    */
/*  result = R * 2 ^ (N	+ 1)						    */
/****************************************************************************/
double exp(double x)
{
    double g, z, q, p;
    int n;

    /*************************************************************************/
    /* check if input would produce output out of the range of this function */
    /*************************************************************************/
    if (x > MAXX) { errno = ERANGE; return (HUGE_VAL); }

    if (x < 0) n = (int) (x * INVLOGe2 - 0.5);    /* since (int) -1.5 = -1.0 */
    else       n = (int) (x * INVLOGe2 + 0.5);

    /*************************************************************************/
    /* g = x - n * ln(2) (but more mathematically stable)                    */
    /*************************************************************************/
    g  = (x - n * C3) - n * C4;

    /*************************************************************************/
    /* determine polynomial expression                                       */
    /*************************************************************************/
    z  = g * g;

#if BITS <=29
    p = (EXP1 * z + EXP0) * g;
    q = EXQ1 * z + EXQ0;
#elif BITS>=30 && BITS<=42
    p = (EXP1 * z + EXP0) * g;
    q = (EXQ2 * z + EXQ1) * z + EXQ0;
#elif BITS>=43 && BITS<=56
    p = ((EXP2 * z + EXP1) * z + EXP0) * g;
    q = (EXQ2 * z + EXQ1) * z + EXQ0;
#else
    p = ((EXP2 * z + EXP1) * z + EXP0) * g;
    q = ((EXQ3 * z + EXQ2) * z + EXQ1) * z + EXQ0;
#endif

    /*************************************************************************/
    /* exp(x) = exp(g) * 2 ^ (n + 1)                                         */
    /*************************************************************************/
    return ldexp(0.5 + p / (q - p), n + 1); 
}