📄 channelcapacity.m
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clc;clear all;
r = input('the number of input r=');
s = input('the number of output s=');
p_matrix=zeros(r,s);
fprintf('input the value of p_matrix:\n')
for i=1:r
for j=1:s
p_matrix(i,j)=input('p_matrix=');
if p_matrix(i,j)<0
error('Do not accord with the distribution')
end
end
end
for i=1:r
sum_line(i)=0;
for j=1:s
sum_line(i)=sum_line(i)+p_matrix(i,j);
end
end
for i=1:r
if (sum_line(i)<=0.999999||sum_line(i)>=1.000001)
error('Do not accord with the distribution')
end
end
e=input('input the iterative precision:');
for i=1:r
p(i)=1.0/r; % the initial probability accord with uniform distribution
end
for j=1:s %the sum of q(j)
q(j)=0;
for i=1:r
q(j)=q(j)+p(i)*p_matrix(i,j);
end
end
for i=1:r %the sum of a(i)
d(i)=0;
for j=1:s
if(p_matrix(i,j)==0)
d(i)=d(i)+0;
else
d(i)=d(i)+p_matrix(i,j)*log(p_matrix(i,j)/q(j));
end
end
a(i)=exp(d(i));
end
u=0;
for i=1:r %calculate the value of u
u=u+p(i)*a(i);
end
IL=log2(u); %calculate the value of IL
IU=log2(max(a));%calculate the value of IU
n=1;
while((IU-IL)>=e) %the iterative calculation
for i=1:r
p(i)=p(i)*a(i)/u; %refresh the value of p(i)
end
for j=1:s %calculate the value of q(j)
q(j)=0;
for i=1:r
q(j)=q(j)+p(i)*p_matrix(i,j);
end
end
for i=1:r %calculate the value of a(i)
d(i)=0;
for j=1:s
if(p_matrix(i,j)==0)
d(i)=d(i)+0;
else
d(i)=d(i)+p_matrix(i,j)*log(p_matrix(i,j)/q(j));
end
end
a(i)=exp(d(i));
end
u=0;
for i=1:r %calculate the value of u
u=u+p(i)*a(i);
end
IL=log2(u); %calculate the value of IL
IU=log2(max(a));%calculate the value of IU
n=n+1;
end
fprintf('the channel matrix is:\n');
disp(p_matrix);
fprintf('the iterative number n=%d\n',n);
fprintf('the channel capacity C=%fbit/symbol',IL);
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