popd1

来自「linux脚本编程的例子」· 代码 · 共 13 行

popd ()
{
    if [ -n "$DIR_STACK" ]; then
        DIR_STACK=${DIR_STACK#* }
        cd ${DIR_STACK%% *}
        echo "$PWD"
    else
        echo "stack empty, still in $PWD."
    fi
}