pushd1

来自「linux脚本编程的例子」· 代码 · 共 14 行

TXT
14
字号
pushd (){    dirname=$1    if cd ${dirname:?"missing directory name."}   # if cd was successful    then        DIR_STACK="$dirname ${DIR_STACK:-$PWD' '}"  # push the directory        echo $DIR_STACK    else        echo still in $PWD.                       # else do nothing    fi}

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