pushd1
来自「linux脚本编程的例子」· 代码 · 共 14 行
TXT
14 行
pushd (){ dirname=$1 if cd ${dirname:?"missing directory name."} # if cd was successful then DIR_STACK="$dirname ${DIR_STACK:-$PWD' '}" # push the directory echo $DIR_STACK else echo still in $PWD. # else do nothing fi}
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